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From Table 11.14, we use the following heuristics:
                                                                         3 0.5
                          Rule 2: F  = uρ  υ 0.5  = 1.2 → 1.5 m/s(kg/m )
                                     s
                          Rule 3: ΔP       = 0.007 bar
                                      tray
                          Rule 4: ε tray  = 60 – 90 %

                                                                                                               α )  = 2.28
                          x oυhd  = 0.9962, x oυhd  = 0.0308, α oυhd  = 2.44, α  = 2.13, α   geom aυe  = (α oυhd bot  0.5
                                                                               bot
                          N min  = ln{ [0.9962/(1 – 0.9962)]/[0.0308/(1 – 0.0308)]} /ln (2.28) = 10.9
                          R min  = {142.2/105.6}/(2.28 – 1) = 1.05
                          Range of R = (1.2 → 1.5)R      min  = 1.26 → 1.58

                          N theoretical  ≈ (2)(10.9) = 21.8
                          ε tray  = 0.6
                          N      ≈ (21.6/0.6)(1.1) = 40 trays
                            actual
                          ρ  = 6.1 kg/m  3
                           υ
                                                0.5
                          u = (1.2 → 1.5)/6.1  = 0.49 → 0.60 m/s
                          Vapor flowrate (Stream 13) = 22,700 kg/h
                                                       3
                          Vol. flowrate, υ = 1.03 m /s
                                                                                         0.5
                                            0.5
                          D tower  = [4υ/πu]  = [(4)(1.03)/(3.142)/(0.49 → 0.60)]  = 1.64 – 1.48 m
                          ΔP tower  = (N actual )(ΔP tray ) = (40)(0.007) = 0.28 bar


                    A  comparison  of  the  actual  equipment  design  and  the  predictions  of  the  heuristic  methods  are  given
                    below.









                          f.  H-101
                          From Table 11.11, we use the following heuristics:
                          Rule 13: Equal heat transfer in radiant and convective sections
                                                                2
                                        radiant rate = 37.6 kW/m , convective rate = 12.5 kW/m      2

                                                              Duty = 27,040 MJ/h = 7511 kW
                                                                                    2
                                                                                                2
                          Area radiant section = (0.5)(7511)/(37.6) = 99.9 m  (106.8 m  in Table 1.7)
                                                                                                      2
                                                                                          2
                          Area convective section = (0.5)(7511)/(12.5) = 300.4 m  (320.2 m  in Table 1.7)
                    From the earlier worked examples, it is clear that the sizing of the equipment in Table 1.7 agrees well
                    with the predictions of the heuristics presented in this chapter. Exact agreement is not to be expected.
                    Instead, the heuristics should be used to check calculations performed using more rigorous methods and to
                    flag any inconsistencies.


                    11.3 Summary





                    In this chapter, we have introduced a number of heuristics that allow us to check the reasonableness of the
                    results of engineering calculations. These heuristics or guidelines cannot be used to determine absolutely
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