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10. Molecular Phylogeny
                              212
                              at time t given that it starts in A at time 0. We will derive a system of
                              coupled ordinary differential equations obeyed by q AY (t) and p AG (t). The
                              entry p AG(t)of P(t) is the probability that the chain is in G at time t given
                              that it starts in A at time 0. By the same reasoning that led to the forward
                              equation (10.5), we have
                                      q AY (t + h)= q AY (t)(1 − δh − κh)+ p AG (t)(γ + λ)h
                                                     +[1 − q AY (t) − p AG(t)](γ + λ)h + o(h),
                              where 1 − q AY (t) − p AG (t) equals the probability p AA (t) of being in A at
                              time t. Forming the obvious difference quotient and letting h → 0 yields
                              the differential equation
                                                  q   AY  (t)  = −c 1 q AY (t)+ c 2 ,
                              where

                                                     c 1  = δ + κ + γ + λ
                                                     c 2  = γ + λ.
                              This equation can be solved by multiplying by the integrating factor e c 1t
                              and isolating the terms [q AY (t)e c 1 t
                                                            ] involving q AY (t) on the left side of the
                              equation. These manipulations yield the solution
                                                               c 2    −c 1t
                                                   q AY (t)  =   (1 − e  )               (10.12)
                                                               c 1
                              satisfying the initial condition q AY (0) = 0.
                                To solve for p AG (t), write the forward approximation
                                       p AG(t + h)= p AG(t)(1 −  h − γh − λh)+ q AY (t)κh
                                                      +[1 − q AY (t) − p AG (t)]αh + o(h).

                              This leads to the differential equation
                                             p    (t)  = −c 3 p AG (t)+ c 4 q AY (t)+ α,
                                              AG
                              where

                                                     c 3  =   + α + γ + λ
                                                     c 4  = κ − α.

                              Substituting the solution (10.12) for q AY (t), one can straightforwardly ver-
                              ify that this last differential equation has solution

                                                        c 2 c 4 + αc 1  c 2 c 4  −c 1t
                                            p AG(t)  =           −           e
                                                          c 1 c 3   c 1 (c 3 − c 1 )
                                                          c 2 c 4 − α(c 3 − c 1 )  −c 3 t
                                                       +                 e               (10.13)
                                                            c 3 (c 3 − c 1 )
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