Page 94 - APPLIED PROCESS DESIGN FOR CHEMICAL AND PETROCHEMICAL PLANTS, Volume 1, 3rd Edition
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80                        Applied Process Design for Chemical and Petrochemical Plants









            1                                                                                                  0








             K












                                                                                  tan 812 = (D,  - D1)/2L

                                                                               h=




                 0    10   20   30   40   50    60
                           e  IN  DEGREES
                                RESISTANCE  COEFFICIENTS FOR  INCREASERS  AND  DIFFUSERS

             Figure 2-16.  Resistance coefficients for increasers and diffusers for water.  Reprinted by permission, Hydraulic Institute, Engineering Data
             Book, 1st Ed.,  1979, Cleveland, Ohio.


             Sudden Enlargement or Contraction [21                   For sudden pipe system contractions as represented in
                                                                   Figure  2-12A  through  2-16, the values of  the  resistance
               For sudden enlargements in a pipe system when there   coefficient,  K,  can  be  read  from  the  charts.  For  more
             is  an abrupt change from a smaller pipe flowing into a   details for various  angles of  enlargements and  contrac-
             larger pipe, the resistance coefficient, K, is given by:   tions, see References [3] and [2].
               For sudden enlargement:

               K1  = (1 - D1P/D24)* = (1 - p2)'           (2-28)     For sudden contractions:

             where subscripts 1 and 2 refer to the smaller (upstream)
             and larger pipes respectively [ 31,                     K1 0.5 (1 - dl2/d2')  = 0.5 (1 - p')       (2-36)
             0 r,

               hf = K (v2/2g), ft of fluid, friction      (2-27)     Note: Subscripts 1 and 2 indicate small and large pipes
                                                                   respectively.
               hf = Kl  [l - (d12/dz')z]z (vZ1,/2g), ft of fluid   (2-34)

               K1  = (1 - dl'/d~2)z                       (2-35)     Then, h,  = K,  (v12/2g), ft               (2-27)
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