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               5-14


                     Chebyshev's
                                                                                 2
                       Inequality   For any random variable X with mean   and variance   ,
                                                           P10 X    0    c 2   1
c 2

                                    for c > 0.



                                 This result is interpreted as follows. The probability that a random variable differs from its
                                                                                    2
                                 mean by at least c standard deviations is less than or equal to 1 c . Note that the rule is useful
                                 only for c > 1.
                                    For example, using c = 2 implies that the probability that any random variable differs
                                 from its mean by at least two standard deviations is no greater than 1 4. We know that for a
                                 normal random variable, this probability is less than 0.05. Also, using c   3 implies that the
                                 probability that any random variable differs from its mean by at least three standard deviations
                                 is no greater than 1 9. Chebyshev’s inequality provides a relationship between the standard
                                 deviation and the dispersion of the probability distribution of any random variable. The proof
                                 is left as an exercise.
                                    Table S5-1 compares probabilities computed by Chebyshev’s rule to probabilities com-
                                 puted for a normal random variable.

               EXAMPLE S5-8      The process of drilling holes in printed circuit boards produces diameters with a standard
                                 deviation of 0.01 millimeter. How many diameters must be measured so that the probability is
                                 at least 8 9 that the average of the measured diameters is within 0.005 of the process mean
                                 diameter  ?
                                    Let X 1 , X 2 , . . . , X n be the random variables that denote the diameters of n holes. The aver-
                                 age measured diameter is X   1X   X    p     X 2
n.  Assume that the X’s are independent
                                                                          n
                                                            1
                                                                2
                                                                                         2
                                 random variables. From Equation 5-40,  E1X 2    and V1X 2   0.01 
n.  Consequently, the
                                                          2
                                                             1 2
                                 standard deviation of X  is (0.01  n) . By applying Chebyshev’s inequality to  , X
                                                                        2   1
 2    2
                                                        P10 X   0   c10.01 
n2  2   1
c
                                 Let c = 3. Then,
                                                                         2  1
 2
                                                        P10 X   0   310.01 
n2  2   1
9
                                 Therefore,

                                                                         2  1
 2
                                                        P10 X   0   310.01 
n2  2   8
9

                                             Table S5-1 Percentage of Distribution Greater than  c Standard
                                                       Deviations from the Mean
                                                            Chebyshev’s Rule            Normal
                                             c         for any Probability Distribution  Distribution
                                             1.5             less than 44.4%            13.4%
                                             2               less than 25.0%             4.6%
                                             3               less than 11.1%             0.27%
                                             4               less than 6.3%              0.01%
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