Page 385 - Applied Statistics And Probability For Engineers
P. 385

c10.qxd  5/16/02  1:30 PM  Page 329 RK UL 6 RK UL 6:Desktop Folder:TEMP WORK:MONTGOMERY:REVISES UPLO D CH114 FIN L:Quark Files:






                       10-2 INFERENCE FOR A DIFFERENCE IN MEANS OF TWO NORMAL DISTRIBUTIONS, VARIANCES KNOWN  329


                       Assumptions
                                       1.  X , X , p , X 1n 1  is a random sample from population 1.
                                               12
                                            11
                                       2.  X , X , p , X 2n 2  is a random sample from population 2.
                                            21
                                               22
                                       3.  The two populations represented by X and X are independent.
                                                                              2
                                                                         1
                                       4.  Both populations are normal.
                                       A logical point estimator of      is the difference in sample means X   X .  Based
                                                                                                       2
                                                               1
                                                                    2
                                                                                                  1
                                   on the properties of expected values
                                                        E1X   X 2   E1X 2   E1X 2        2
                                                                       1
                                                           1
                                                                                    1
                                                                2
                                                                              2
                                                          is
                                   and the variance of X 1   X 2
                                                                                    2    2
                                                                                    1     2
                                                       V1X   X 2   V1X 2   V1X 2    n 1     n 2
                                                               2
                                                                              2
                                                                       1
                                                           1
                                   Based on the assumptions and the preceding results, we may state the following.
                                       The quantity
                                                                             1
                                                                                  2
                                                                  X 1    X   1     2
                                                                        2
                                                             Z                                       (10-1)
                                                                         2    2
                                                                          1    2

                                                                      B  n 1  n 2
                                       has a N(0, 1) distribution.

                                       This result will be used to form tests of hypotheses and confidence intervals on      .
                                                                                                        1
                                                                                                            2
                                                                                                   ˆ
                                   Essentially, we may think of      as a parameter  , and its estimator is     X   X 2
                                                                  2
                                                                                                        1
                                                             1
                                                2    2      2
                                   with variance  ˆ    1
n    2  
n .  If   is the null hypothesis value specified for  , the test
                                                       1
                                                               2

                                                                    0
                                                 ˆ
                                   statistic will be 1	    2
  ˆ .  Notice how similar this is to the test statistic for a single mean

                                                      0
                                   used in Equation 9-8 of Chapter 9.
                 10-2.1   Hypothesis Tests for a Difference in Means, Variances Known
                                   We now consider hypothesis testing on the difference in the means      of two normal
                                                                                            1
                                                                                                 2
                                   populations. Suppose that we are interested in testing that the difference in means      is
                                                                                                      1
                                                                                                           2
                                   equal to a specified value   . Thus, the null hypothesis will be stated as H :         .
                                                                                                        2
                                                                                                   1
                                                          0
                                                                                                            0
                                                                                                0
                                   Obviously, in many cases, we will specify     0 so that we are testing the equality of two
                                                                       0
                                   means (i.e., H :      ). The appropriate test statistic would be found by replacing      2
                                              0
                                                 1
                                                      2
                                                                                                        1
                                   in Equation 10-1 by   , and this test statistic would have a standard normal distribution under
                                                     0
                                     . That is, the standard normal distribution is the reference distribution for the test statistic.
                                   H 0
                                   Suppose that the alternative hypothesis is H :          . Now, a sample value of x   x 2
                                                                                                        1
                                                                              2
                                                                                   0
                                                                         1
                                                                      1
                                   that is considerably different from   is evidence that H is true. Because Z has the N(0, 1)
                                                                 0
                                                                                                0
                                                                                 1
   380   381   382   383   384   385   386   387   388   389   390