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5A.4 MULTIPLE BOND FORMATION: SYNTHESIS OF SODIUM AZIDE  135


                  REVIEW PROBLEM 5A.5
                  Another synthesis of hydrazine involves the oxidation of urea, (NH ) C=O, with
                                                                          2 2
                  sodium hypochlorite:

                       (H N) C=O + NaOCl + 2NaOH → N H + H O + NaCl + Na CO
                         2  2                          2  4  2             2  3
                  Suggest a mechanism.




                      MULTIPLE BOND FORMATION: SYNTHESIS OF SODIUM AZIDE
               5A.4
               Nitrogen-on-nitrogen attack followed by elimination leads to N–N multiple bonds. A good
               example is the synthesis of sodium azide (NaN ). Sodium azide has been widely used as the
                                                    3
               gas-forming agent in automobile airbags; nowadays, however, a milder explosive is gen-
               erally preferred. The synthesis involves the interaction of nitrous oxide (N O) and molten
                                                                           2
                                             ∘
               sodium amide (NaNH ) at about 190 C.
                                 2
                                  2NaNH + N O → NaN + NaOH + NH                  (5A.16)
                                         2   2        3             3
                                             –
               The structure of the azide anion (N ) indicates that the NH  –  and N O nitrogens must
                                            3                    2      2
               somehow come together and the H and O atoms somehow stripped away. A reasonable
                                                     –
               working hypothesis is that the amide ion (NH ) acts as a nucleophile and attacks one of
                                                    2
               the N O nitrogens. For NH 2 –  attacking the terminal nitrogen of N O, the following pathway
                                                                  2
                    2
               may be envisioned:
                                                  N   N
                             +   −                       −            N   N
                         N   N   O         H   N        O
                                                                H   N       OH   (5A.17)
                  H   N                          H                    −
                     −
                        H
                                                                             –
               The NH proton of the intermediate can then be picked up by a second NH , producing
                                                                            2
                               –
                      –
               NH ,N , and OH , as shown below:
                  3
                      3
                                                       H
                     H              N   N                     −       −
                      −  N   H   N        OH             N +  N   N   N
                                  −                   H
                      H                                 H               OH
                                                                                 (5A.18)
                                 −        −             −   +   −    −
                                 N   N    N            N    N   N +  OH
                                            OH
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