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Dynamics  of Inviscid  Fluids                                                                77



             5.4         Example
                 In  the  sequel  we  will  illustrate  a  particular  transformation  (mapping),
                                          ;                ;                ;                           a
             namely  the  Joukovski  transformation  (see  section  2.5.3),  z  =  24+  —.
             By  this  transformation  the  complex  potential  of  a  uniform  flow  becomes

             f(z)  =U  (2  + a;  )  i.e.,  the  potential  for  a  uniform  flow  past  a  circular

             cylinder  of  radius  a,  U  being  the  magnitude  of  the  velocity  at  far  field.
                 This  transformation,  z=  2’  +  oe  where  b?  <  a”,  allows  the  conformal
             transformation  of  a  circle  of  radius  @  centered  at  P(z'p,  yp)  from  the
             second  quadrant  Oz'y’  onto  a  so-called  Joukovski  airfoil  (profile)  in  the
             Oxy  plane.

                 Let  us  now  consider  a  uniform  flow  of  velocity  U  in  the  positive  Ox
             direction  past  the  above  Joukovski  airfoil.  In  particular,  its  sharp  trailing
             edge  at  x  =  2b,  is  the  image  of  the  point  Q  at  z’  =  b  where  Oz’  is  crossed
             by  the  above  circle.
                 The  magnitude  V  of  the  velocity  in  the  Oxy  plane  is  related  to  the
              magnitude  V’  of  the  velocity  in  the  Oz’y'  plane  by  the  relation


                                                                 ef
                                                               dz!

                                                     df
                                                                     3
                                                     dz         dz
                                                               dz!


             1.e.,
                                                              y!
                                                  V=                aT:                               (2.8)
                                                         1  (8)”


                 We  remark  that  if  the  velocity  V’  #  0  at  Q  where  2’  =  b,  then  the
             velocity  V  at  the  sharp  trailing  edge  z  =  2b  becomes  infinite,  which
             is  a  contradiction  with  the  Joukovski—Kutta  condition.  Thus,  we  must

             impose  that  the  point  Q  on  the  circle  be  a  stagnation  point;  this  goal
             may  be  reached  if  we  create  a  clockwise  circulation  I’  on  the  circle,
              and  this  circulation  is  then  conserved  by  the  conformal  mapping.  The
             magnitude  of  this  circulation  is  [T  =  4xaU  sin@  =  4ay,U  and  the  flow
             past  the  circle  is  then  constructed  by  adding  to  the  uniform  stream  a
             doublet  and  a  point  vortex,  so  that  we  get  the  complex  potential  of  the

             resultant  flow
                                                         2                      fot
                            pauls  —zp4  —  -  + i2yplog  (#                         =e).


                                                          zp                       a
             Here  the  constant  term  —i2y  loga  has  been  added  but  the  values  of  the

              stream  function  WV  on  the  circle  do  not  change  after  this  superposition.
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