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162            SECTION 2                                        STRENGTHENING AND REPAIR WORK



                            Proof: Calculate the c.g. of loads where resultant is acting.
                            Assuming maximum BM occurs under middle heavy wheel at B.
                                        M  3 R1 8 (L/2 6 x) 6 4k 8 14 ft
                                          2
                                                                   –
                                        R1 3 Resultant 8 (L/2 4 x 6 x)/L
                                                             –
                                        R1 3 36 8 (L/2 4 x 6 x)/L                                 (4.25)
                               For maximum BM rate of change of moment 3 0
                                                         –
                                    dM /dx 3 Resultant 8 (x/L 6 2x/L) 3 0
                                       2
                                          –
                                          x 3 x/2
                            Procedure for HL-93 truck:
                            Replace 3 wheel loads by a single resultant of wheel loads 3 $ (16 4 16 4 4) 3 36 kip
                               Locate the resultant force from nearest wheel by taking moments about that wheel.
                               $ M 3 0 at wheel B
                               (36   X) 4 16   14 ft 6 4   14 ft 3 0;
                               Distance (to c. g. O) X 3 (12   14)/36 3 14/3 3 4.667 ft from wheel B.
                               Calculate reactions at supports: For a given live load, reactions will vary with span
                        lengths. Taking moment at about support 2,
                               R1 8 L 6 36 (L/2 6 2.333 ft) 3 0;
                               Reaction R1 3 18L – 60;
                                              Mmax 3 18(L-1.55) (L-14)/L (Kip-ft)                 (4.26)
                                                  Vmax 3 24(3L-28)/L (Kips)                       (4.27)

                               Comparisons of numerical values are shown in Table 4.4.
                         4.11.2  Procedure for HL-93 Alternate Tandem Truckloads (Table 4.5)

                                     Author’s BM formula for tandem loads = 12.5 (L-4) (Kip-Ft)   (4.28)
                                     Author’s shear formula for tandem loads = 50 (1-2/L) (Kips)   (4.29)
                            Single lane moments and forces are given. For multiple lanes, live load will be increased
                        linearly. A multiple-lane reduction factor is allowed. A 6-foot transverse distance between tires
                        is assumed.
                            HL-93 maximum lane loads
                                                               2
                            Author’s use of simplifi ed formula 3 w L /8
                            Table 4.6 shows total HL-93 truck and lane load moment and shear $ (Lane loads of 0.64
                        kips/ft 4 HS-20) and $ (Lane loads of 0.64 kips/ft 4 Alternate tandem trucks)

                        4.11.3  Envelope of Design Moments and Shears
                            Design Moment 3 Total HL-93 moment 8 Impact factor 8 Applicable distribution factor
                        for single lane.
                            Dynamic load allowance (impact factors) 3 1.33 applicable to truckloads only. For reduced
                        posted speed, a lower factor may be used.
                            For multiple lane live loads, a reduction in total live load is applicable.
                            Fatigue dynamic load allowance (for fatigue analysis)  3 1.15 applicable to truckloads
                        only.
                            Comparison of maximum live load moments for internal beam. For truck load versus tandem
                        load a comparative study is shown in Table 4.5.
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