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CHAPTER 6                       APPLICATIONS OF BRIDGE DESIGN AND RATING METHODS            275



        6. M 3 A  f  (d 6 a/2)
              n
                   s
                       s
                    y
        7. Minimum reinforcement required to develop M r
              Lesser of 1.2 M  or 1.33 M  (LRFD 5.7.3.3.2)
                                     u
                            cr
              M  3 ) M  Eq. (6-4)
                r
                       n
           1.2 M 3 1.2 (f 4 f ) S 6 M d,,nc  (S / S 6 1) (LRFD 5.4.2.6)
                cr
                        r
                                              b
                               bc
                            pb
                                          bc
              S 3 I/ y t
                bc
               f 3 0 (no prestress)
                pb
            M d,,nc  3 0 (non-composite dead load moment)
        8. Critical section for shear (LRFD 5.8.3.2)
            Effective shear depth d  3 M  / (A f  f A ) (LRFD 5.8.2.9)
                                     n
                                                 ps
                               v
                                         s y 4 ps
            Maximum of 0.9 d  and 0.72 h LRFD Eq. (C5-9)
                            e
            or distance between resultants of tensile and compressive forces.
            Compute dead load shear V  and V DW
                                   DC
             V 3 V 4 Vs
              n
                   c
                                0.5
             V 3 0.0316 b  d  (fc1)
              c
                         v
                           v
            Vs 3 d  Cot 0 (A f )
                  v
                           s y
        6.9.1  General Load Rating Equation (LRFD 6.4.2)
            RF 3 [C 6 (  ) (DC) 6 (  ) (DW) ?    (P)] /    (LL 4 IM) (EQ 6-1)
                                    DW
                                                P
                                                        L
                        DC
        1. Factors for inventory rating:    3 1.25;    3 1.25;    3 1.75
                                                           LI
                                                DW
                                     DC
            Factors for operating rating:    3 1.25;    3 1.25;    3 1.35
                                                           LO
                                                DW
                                     DC
            Operating rating 3 Inventory rating x (  /  )
                                              LI
                                                 LO
        2. Design rating equation
            Strength I limit state:
            C 3 () ) () ) ()) R n
                      s
                   c
            RF 3 [() ) () ) ()) R 6 (  ) (DC) 6 (  ) (DW)] /    (LL 4 IM) (LRFD 6.5.4.1)
                    c
                                    DC
                                                DW
                                                           L
                               n
                        s
            Condition factor () ) 3 1.0 for no deterioration. (LRFD 6.4.2.3)
                             c
            System factor () ) 3 1.0 for a slab bridge. (LRFD 6.4.2.4)
                          s
            Resistance factor ()) 3 0.9 for flexure (LRFD 5.5.4.2)

            IM 3 1.33
        3. Compute legal load rating
        4. Compute permit load rating
        Table 6.10  Rating summary table.
                               Design Live Load Rating  Legal Load Rating  Permit Load Rating
         Limit State           Inventory  Operating  T3   T3S2    T3-3
         Strength I   Flexure
                     Shear
         Strength II  Flexure
                     Shear
         Service II
         Fatigue
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