Page 205 - Calculus Demystified
P. 205

CHAPTER 6
                     192
                                                                 y  Transcendental Functions



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                                                              Fig. 6.26



                                    Summary of Key Facts About the Inverse Trigonometric Functions
                                                       π        π
                                         Sin x = sin x, −  ≤ x ≤  ;  Cos x = cos x, 0 ≤ x ≤ π;
                                                       2        2
                                                       π        π
                                        Tan x = tan x, −  <x <    ;  Cot x = cot x, 0 <x <π;
                                                        2        2
                               Sec x = sec x, x ∈[0,π/2) ∪ (π/2,π]; Csc x = csc x, x ∈[−π/2, 0) ∪ (0,π/2].
                                d    −1        1                    d    −1          1
                                  Sin  x = √        , −1 <x < 1;      Cos  x =−√         , −1 <x < 1;
                                dx            1 − x 2              dx              1 − x 2
                                d    −1       1                     d     −1        1
                                  Tan   x =       , −∞ <x < ∞;        Cot   x =−        , −∞ <x < ∞;
                               dx           1 + x 2                 dx            1 + x 2
                                 d    −1          1                 d    −1            1
                                   Sec  x =     √       , |x| > 1;    Csc  x =−      √       , |x| > 1;
                                dx          |x|·  x − 1            dx            |x|·  x − 1
                                                   2
                                                                                        2

                                             du         −1              du           −1
                                          √        = Sin  u + C;      √       =−Cos     u + C;
                                            1 − u 2                    1 − u 2

                                           du           −1              du            −1
                                                du = Tan  u + C;            du =−Cot    u + C;
                                          1 + u 2                     1 + u 2

                                           du           −1                du              −1
                                          √        = Sec  u + C;          √       =−Csc     u + C.
                                                                             2
                                             2
                                      |u|·  u − 1                     |u|·  u − 1
                               You Try It: What is the derivative of Sec −1 2
                                                                      x ?
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