Page 249 - Calculus Demystified
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CHAPTER 8
                     236
                                   EXAMPLE 8.16                 Applications of the Integral
                                   Imagine that a water tank in the shape of a hemisphere of radius 10 feet
                                   isbeing pumped out (Fig. 8.26). Find the work done in lowering the water
                                   level from 1 foot from the top of the tank to 3 feet from the top of the tank.


                                                                   Radius at depth x
                                                                           _  2
                                                                   equals √100   x










                                                              Fig. 8.26


                                   SOLUTION
                                     A glance at Fig. 8.27 shows that the horizontal planar slice of the tank, at the
                                                                           √
                                                                                    2
                                   level x feet below the top, is a disk of radius  100 − x . This disk therefore
                                                            2
                                   has area A(x) = π · (100 − x ). Thus a slice at that level of thickness  x will
                                   have volume
                                                                       2
                                                    V(x) = π · (100 − x ) · x

                                                                          100
                                                                 x
                                                                          _  2
                                                                      √100   x




                                                              Fig. 8.27

                                   and (assuming that water weights 62.4 pounds per cubic foot) weight equal to
                                                                          2
                                                    w(x) = 62.4π · (100 − x ) · x.
                                     Thus the work in raising this slice to the top of the tank (where it can then
                                   be dumped) is
                                                    
               2
                                            W(x) = 62.4π · (100 − x ) · x · x foot-pounds.
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