Page 265 - Calculus Demystified
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CHAPTER 8
                     252
                                                    h = 16      Applications of the Integral
                                                                            4√2




                                                                    _
                                                                  24   h

                                                    h = 24
                                                              Fig. 8.43



                   8.7 Numerical Methods of Integration


                               While there are many integrals that we can calculate explicitly, there are many
                               others that we cannot. For example, it is impossible to evaluate
                                                                   2
                                                                e −x  dx.                           (∗)


                               Thatistosay,itcanbeprovedmathematicallythatnoclosed-formantiderivativecan
                               be written down for the function e −x 2 . Nevertheless, (∗) is one of the most important
                               integrals in all of mathematics, for it is the Gaussian probability distribution integral
                               that plays such an important role in statistics and probability.
                                  Thus we need other methods for getting our hands on the value of an integral.
                               One method would be to return to the original definition, that is to the Riemann
                               sums. If we need to know the value of
                                                                 1  2
                                                                 e −x  dx
                                                               0
                               then we can approximate this value by a Riemann sum
                                   1   2            2              2              2           2
                                    e −x  dx ≈ e −(0.25)  · 0.25 + e −(0.5)  · 0.25 + e −(0.75)  · 0.25 + e −1  · 0.25.
                                  0
                               A more accurate approximation could be attained with a finer approximation:

                                                      1    2                2
                                                                  10
                                                        e −x  dx ≈   e −(j·0.1)  · 0.1            (∗∗)
                                                     0
                                                                  j=1
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