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120  FLOW  OF  FLUIDS



                   EXAMPLE 6.15                                    Eq.  (6.128),
                   Pressure Drop in Flow of Nitrogen and Powdered Coal
                Powdered coal of 100 pm dia and 1.28 specific gravity is transported   AP/L = 9.806[1282(1-  0.9959) + 1.14(0.9959)]
                vertically through  a  1-in.  smooth line at the rate  of  15g/sec.  The   + (2/0.0254) [0 .0076(1.14) (6.1)'
                carrying gas is  nitrogen  at  1 atm  and 25°C  at  a  linear velocity of
                6.1 m/sec.  The density of  the gas is 1.14 kg/m3 and its viscosity is   + 0.0031( 1282)(0.0041) (5.608)']
                1.7(10-')  N sec/m'.  The equations of Table 6.10 will be used for the   = 51.54 + 11.13 + 25.38 + 40.35 = 128.4 Pa/m.
                various parameters  and ultimately the pressure gradient AP/L will
                be found:                                          With Eqs. (5) and (13), no trial calculations are needed.
                                  9.806(1.14)(1282  - 1.14)           Eq. (13),  Up = 6.1[1-  0.68(0.0001)0~92(1282)0~5
                             =
                   Eq'  (8)9           [1,7(10-5)]2                                x (1. 14)-0.2(0.0254)-0.54]
                              0. 153(9.806)0~71(0.0001)"4( 1282 - 1. 14)0.71     = 5.88 m/sec,
                   Eq. (lo),  Ut=
                                      1.14°~29[1.7(10-5)]0~43         Eq.  (15),   E  = 1 -0.0231/5.78=0.9960,
                             = 0.37 m/sec (0.41 m/sec by Stokes' law),   Eq. (5),  f, = 0.0285v9.806(0.0254)/5.88  = 0.00242.
                                         0.015            0.0231
                   Eq. (15),   E  = 1 -               =I--            Therefore,  the  solid  frictional gradient  is  obtained  from  the
                                (~~/4)(0.0254)'(1282 - 1.14)Up   UP  '   calculated value 40.35 in the ratio of  the friction factors.
                                                              (1)
                   Eq. (14),  Up = 6.1 - 0.45Vl +f,U;/2(9.806)(0.0254)   (AP/L)solidfriction 40.35(0.00242/0.0031) = 31.5 Pa/m.
                                                                                   =
                             = 6.1 - 0.45Vl+ 2.007fU;         (11)
                   Eq. (71,   f,=   &3     6.1 - Up          (111)     10  !  Example  6.15. Fressi~re rft-o
                                                                           P  in  flou  of  nitrosen  and PO
                Equations  (I), (11), and  (111) are  solved  simultaneously with  the   wdercd  coal
                results:                                               28  IFIPUT  U
                                                                       38 E=1-.8231NU  !  (Eq  1)
                     E = 0.9959  and  Up = 5.608,                      48  F=.OB3151*(l-E:~,E'3~(.4~~(1-
                                                                           E)f<6.l-U:>)*-.979  !  (E4 111)
                For the calculation of  the pressure drop,             58  G=-U+6.1-.45Y~1+2.887~F~~i*~~
                                                                           *.5  !  <5h#Uld =  8)
                    f, = 0.0031  (Yang equation),                      68 PRI t4T  "U=" j U
                                                                       78 PRINT  "G="jG
                       DU+p,-  0.0254(6.1)( 1.14) -                    88  GOTO  28  !  (if  G  is nor:  suffi
                   Ref =                  -  10,390.
                         Pf     1 .7(10r5)                                 cientlr close to  zero1
                                                                       98  END
                Therefore, Round's  Eq. (6.21) applies:
                                                                      u=  5.688
                   f -1                                              G=-.88#859348861
                   f - $  ~  = 0.0076   ~  d
                             ~
                                 ~

                varying complexity have been  proposed,  of  which  some important   called minimum fluidization. Beyond this point the solid-fluid mass
                ones are listed in Table 6.10.                      exhibits  flow  characteristics  of  ordinary  fluids  such  as  definite
                   These equations involve the free settling velocity U,,  for which   viscosity  and flow through lines under the influence of  hydrostatic
                separate equations also are shown in the table. At lower velocities   head  difference.  The  rapid  movement  of  particles  at  immersed
                Stokes' law applies, but  corrections must be made at higher ones.   surfaces  results  in  improved  rates  of  heat  transfer.  Moreover,
                The  particle  velocity  Up is  related  to  other  quantities  by  Eqs.   although  heat  transfer  rate  between  particles  and  fluid  is  only
                (12)-(14)  of the table, and the voidage in turn is represented by Eq.   moderate,  1-4 Btu/(hr)(sqft)("F),  the amount of surface is so great,
                (15). In a review of  about 20 correlations, Modi et al. (Proceedings,   10,000-150,000 sqft/cuft,  that  temperature  equilibration  between
                Powder  and  Bulk  Solids Handling  and  Processing  Conference,   phases  is  attained  within  a  distance  of  a  few  particle  diameters.
                Powder Advisory  Center,  Chicago, 1978, cited by  Klinzing, 1981)   Uniformity of temperature, rapid mass transfer, and rapid mixing of
                concluded that  the  correlations of  Konno and Saito (1969) and of   solids  account  for  the  great  utility  of  fluidized  beds  in  process
                Yang  (1976,  1978)  gave  adequate  representation  of  pneumatic   applications.
                conveying  of  coal.  They  are  applied  in  Example  6.15  and  give   As  the  gas  flow  rate  increases  beyond  that  at  minimum
                similar results there.                              fluidization, the  bed  may  continue  to  expand  and  remain  homo-
                                                                    geneous for a time. At a fairly definite velocity, however, bubbles
                6.11.  FLUIDIZATION OF  BEDS  OF  PARTICLES WITH GASES   begin to form. Further increases in flow rate distribute themselves
                                                                    between  the  dense  and  bubble  phases in  some ways  that  are  not
                As  the  flow  of  fluid through  a  bed  of  solid particles increases, it   well  correlated.  Extensive bubbling is  undesirable when  intimate
                eventually reaches a condition at which the particles are lifted out of   contacting between phases is desired, as in drying processes or solid
                permanent  contact with  each other. The onset of  that  condition is   catalytic  reactions.  In  order  to  permit  bubble  formation,  the
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