Page 95 - Chemical Process Equipment - Selection and Design
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4.3.  COMBUSTION GAS  TURBINES AND  ENGINES  67
            Fuel                                 Exhaust
                                                                    Exhaust    6







                    Cornpressor            Expander















           Figure 4.2. Combustion gas turbine arrangements and their thermodynamic diagrams. (a) Basic unit with PV and TS diagrams. (b) Unit with
           an air preheater and TS diagram.



               EXAMPLE 4.2                                        T,  = q(Pz/P1)1’3-5 305(5)1’3.5 = 483K,
                                                                               =
               Performance of P Combustion Gas Turbine                    483 - 305 -
            Atmospheric air at 80°F (305K) is compressed to 5 atm, combined   Tz= 305 +  ~   0.84   - 517 K.
            with fuel at the rate of  1 kg/s,  then  expanded to 1 atm in a power
                                                                  Combustion:
                                  5 atm
                                  1200 K
                                                                  mi =flow rate of  air, kg/kg fuel
                                                                              1200        12Fo
                                                                  0.975(42000) = 1  Cp dT + miLl,  Cp dT
            305 K                                    Steam                   305
                                                                           = 991682 + 771985 mi
                                                                  mi = 51.8
           Air  51.8 kg/s                                         Expansion:
                 Compressor
                                                                  k = 1.33,  k/(k - 1) = 4.0
           turbine.  Metallurgical  considerations  limit  the  temperature  to   Tk  = T3(P4/P1)0.25 1200(0.2)0.z = 802°K
                                                                               =
           1700°F (1200K). The heat capacities of  air and combustion products   T4 = 1200 - 0.89(1200 - 802) = 846°K
           are
               Cp = 0.95 + 0.00021T (K) kJ/kg,
                                                                  Power calculations:
           the  heat  of  comblustioin  is  42,000 kJ/kg,  the  furnace  efficiency  is      517
           0.975, the isentropic efficiency of  the compressor is 0.84, and that of   Compressor: w: = -miAH  = -51.8  /jus GdT
           the expander is 0.89. Find
                                                                              = -51.8(216.98)  = -11.240  kJ/s
                                                                                   517
           a.  the required air rate,                             Expander:  w: = -52.8   Cp dT = 52.8(412.35) = 21,772 kJ/s
           b.  the power loads of  the compressor and expander, and
           c.  the  overall  efficiency  as  a  function  of  the  temperature  of  the   JLOO 046
              exhaust leaving a steam generator.                  Steam generator:  Q‘ = 52.81  Cp dT
                          Point   P   p,   T                                       21772 - 11380 + Q’
                                                                  qt = overall efficiency =
                           1     1         305                                          42000
                           2     5   483   517
                           3     5        1200                    The tabulation  shows efficiency with three  different values of
                           4     1   802   846                 the exhaust temperature.
                           5     1         400
                                                                               T            9s
              Compression :                                                   846      0   0.247
                                                                              600   14311   0.588
              k = 1.4,  k/(k - 1) = 3.5,                                      500   19937   0.722
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