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Below pinch
                      9. CP hot ½ CP cold  FUNDAMENTALS OF ENERGY BALANCES                127
                     10. Note that stream 4 starts at the pinch temperature so can not provide any cooling
                         below the pinch.
                     11. Cannot match stream 1 or 2 with stream 3 at the pinch.
                     12. So, split stream 3 to reduce CP. An even split will allow both streams 1 and 2 to
                         be matched with the split streams adjacent to the pinch, so try this:
                     13. Check the heat available from bringing the hot streams from the pinch temperature
                         to their target temperatures.
                         stream 1 H D 40.0 100   40  D 2400 kW
                         stream 2 H D 30.0 100   60  D 1200 kW
                     14. Check the heat required to bring the cold streams from their source temperatures
                         to the pinch temperature:
                         stream 3 H D 60.0 80   30  D 3000 kW
                         stream 4 is at the pinch temperature.
                                                                                     Ž
                     15. Note that stream 1 can not be brought to its target temperature of 40 Cbyfull
                                                                                  Ž
                         interchange with stream 3 as the source temperature of stream 3 is 30 C, so T min
                         would be violated. So transfer 1800 kW to one leg of the split stream 3.
                     16. Check temperature at exit of this exchanger:
                                                        1800
                                                                  Ž
                                        Temp out D 100       D 55 C, satisfactory
                                                         40
                     17. Provide cooler on stream 1 to bring it to its target temperature, cooling needed:
                                             H cold D 2400   1800 D 600 kW
                     18. Transfer the full heat load from stream 2 to second leg of stream 3; this satisfies
                         both streams.

                     Note that the heating and cooling loads, 2900 kW and 600 kW, respectively, match
                   those predicted from the problem table.



                                             3.18. REFERENCES

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                   DOUGLAS, J. M. (1988) Conceptual Design of Chemical Processes (McGraw-Hill).
                   DRYDEN, I. (ed.) (1975) The Efficient Use of Energy (IPC Science and Technology Press).
                   DUNN,K.S. and TOMKINS, A. G. (1975) Inst. Mech. Eng. Conference on Energy Recovery in the Process Indus-
                       tries, London. Waste heat recovery from the incineration of process wastes.
                   DUNN,R. F.and EL-HALWAGI, M. M. (2003) J. Chem. Technol. Biotechol. 78, 1011. Process integration
                       technology review: background and applications in the chemical process industry.
                   EDMISTER, W. C. (1948) Pet. Ref. 27 (Nov.) 129 (609). Applications of thermodynamics to hydrocarbon
                       processing, part XIII  heat capacities.
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