Page 121 - Chemical equilibria Volume 4
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Molecular Chemical Equilibria     97
                             A change from  X into –X does not alter  y. Therefore, the straight line
                           MA 3 is the axis of symmetry of the different curves.
                                               1
                             – Second  case: β =   β = and  β = (case of reduction of CO 2 by
                                                       2
                                                                 0
                                             1
                                                    3
                                                              2
                           carbon in the presence of nitrogen)
                             Equation [3.77] becomes:
                                   2y 2  =  K
                                            (I)
                                 x  3 −  y
                             From this equation, we draw x, which gives us:
                                     1 ⎛  2y +  K y ⎞  (I)
                                           2
                                 x =   ⎜           ⎟
                                     3 ⎝    K (I)  ⎠

                             The curves  are parabolas (Figure 3.15(b)), with their axis parallel to
                           A 2A 1, and a peak with a the coordinates ( x =− K (I)  /3 , y =− 2K ). These
                                                                                     (I)
                           coordinates are in the ratio  2/ 3.  The space of the peaks is therefore the
                           negative part of the line Δ passing through the origin, with the slope  2/ 3
                           (Figure 3.15(b)).

                             – Third case: β = β =  4  and  β = (reduction of Fe 3O 4 into metal iron
                                                             0
                                               3
                                           1
                                                          2
                           by hydrogen in the presence of nitrogen)
                             Equation [3.77] becomes:
                                 ⎛  2y   ⎞  4  (I)
                                 ⎜       ⎟  =  K
                                 ⎝  x  3 −  y ⎠

                             We deduce the equation for the curves:
                                      x  3       1/4
                                 y =       ( K  (I) )
                                      +
                                    2 K  1/4
                                         r
                             These curves are straight lines issuing from A 2.

                             The relative positions of the equilibrium curves depend on the sign of the
                           enthalpy of the reaction. If, for instance, the reaction enthalpy is positive (i.e.
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