Page 125 - Chemical equilibria Volume 4

y Y Molecular Chemical Equilibria 101
C B

K=4.038
P

K=1
K=0.322 (1600°)

O A x

Figure 3.17. Square diagram for chemical equilibrium
between four gases [SOU 68]

Thus, we deduce from it the expressions:

{CO }
1 x−= 2 [3.102a]
+
{CO 2 } { O }
C
and:

{HO }
1 y−= 2 [3.102b]
+
{ } {H O }
H
2
2
Figure 3.17 gives the square diagram of side length of one unit, and each
peak of which represents a mixture of two gases as shown in Table 3.1, with
the proportions being variables.

O A B C

Mixture CO 2 + H 2 O CO + H 2 O CO + H 2 CO 2 + H 2

Table 3.1. Meaning of each of the corners of the square diagram