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238                                                      Chapter 5

                A  single-stage  turbine  is  limited  to  about  2,500  hp  (1,490  kW)  [31].  The
           efficiencies  plotted  in  Figures  5.19  and  5.20 are  used  for estimating  steam  flow
           rates.  Methods  for determining  more  accurate  efficiencies  and  steam  flow  rates
           are given in Reference 5.31.
                When higher power than a single-stage turbine  can provide is needed, then
           use a multistage turbine  for greater efficiency  and hence steam economy.  Turbine
           efficiencies  for both condensing and noncondensing, multistage  steam turbines are
           given in Figure 5.21.  These  efficiencies  must be  corrected  for the  effect  of using
           superheated steam and the discharge pressure, if it is in the vacuum region.  Thus,

           r|=c s c P r|B                                              (5.45)
           where  r|  is the efficiency  of dry saturated steam, obtained from  Figure 5.19.  The
                  B
           superheat  correction  factor,  GS,  and  the  pressure correction  factor,  CP,  are  also  ob-
           tained  from  Figure 5.21.  In  the upper  part  of  Figures 5.19  and 5.21,  a half-load,
           steam-rate  factor  is plotted.  When the  turbine  is  delivering  half  its  rated  power,
           the  steam flow  rate will be  equal to this  factor  times one half the  full-steam  flow
           rate.
                The ideal final  state, designated with a subscript s, is reached by conducting
           an isentropic process from  state one to  state  two.  This process is given by Equa-
           tionS.11.3 in Table 5.11.
                If  the  steam  leaves  the  turbine  part  liquid  and  vapor,  the properties  of the
           exit  stream  are  determined  by  a  mass  fraction  average  of  the  properties  of pure
           liquid and vapor as given by Equation 5.11.11 to 5.11.13. According  to the phase
           rule,  these properties  are a function  of  one thermodynamic  variable.  Because  the
           inlet  steam  is  superheated,  the  properties  depend  on  two  variables  as  given  by
           Equation  5.11.14  and  5.11.17.  Problem  5.3  illustrates  the  calculation  procedure
           given in Table 5.12.

           Example 5.3  Sizing a Steam-Turbine Drive for a Centrifugal Compressor

           Superheated steam at  13.0 bar (189 psi) and 260.0 °C (500 °F) is being considered
           to drive a compressor. The  shaft  power required by the compressor, P c, is  100 hp
           (74.6kW).  If a  steam turbine rotates  at  3,600 rpm  and  exhausts  at 0.15 bar  (2.18
           psi), what is the power output, steam rate, and steam condensed.
                Follow  the  calculation  procedure  outline  in  Table  5.12.  First,  obtain  the
           thermodynamic  properties  (Equations  5.8.14  to  5.8.21)  at the  inlet  and  discharge
           of the turbine from the steam tables [44]. These are:
           at P] =  1.30 MPa and Tj = 260.0 °C, hi = 2954.0 kJ/kg, s, = 6.8301 kJ/kg-K, and at
           saturation T=  191.6 °C

           at P 2 = 0.015 MPa, T 2 = 45.81 °C, h 2L =  191.83 kJ/kg, h 2V = 2584.7, s 2L = 0.6493
           kJ/kg-K, s 2V = 8.1502 kJ/kg-K




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