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Separator Design                                              299


            3.  Also,  solve  Equations  6.15.15,  6.15.17,  6.15.19,  6.15.21,  and  6.15.23  for D H,
            the inside diameter of the decanter, assuming that the heavy phase flow determines
            the diameter.

            4. The decanter diameter is the larger of the diameters calculated in Steps 2 and 3.

            5.  Round  off D  in  six-inch  (0.152  m)  increments  starting  with  30  in  (0.762  m).
            Below 30 in (0.762 m) use standard pipe.

            6. Calculate v d, the droplet velocity, from Equations 6.15.7 and 6.15.4 to 6.15.6

            7. Calculate to, the dispersed-phase settling time, from Equation 6.15.8.

            8.  Calculate  L$,  the  decanter  length  required  for  settling  of  the  dispersed  phase
            from Equation 6.15.9.

            9. Calculate HD, the dispersion-zone height, from Equation 6.15.10.

            10.  Calculate  Aj, the  interfacial  area  required  for coalescing  the  dispersed  phase
            from Equation 6.15.11.

            12.  Calculate  L, the  decanter  length required  for coalescing  the  dispersed  phase
                         D
            from Equation 6.15.12.
            13. Calculate L, the total length of the decanter, from Equation 6.15.13. Round off
            L in 3 in (0.0762 m) increments, for example, 5.0, 5.25, 5.5, 5.75 ft, etc.





            Example 6.4  Sizing a Liquid-Liquid Separator__________________

            An  oil-water  mixture  is  separated  in  a  decanter.  The properties  of  oil  and  water
            from  an example by Hooper and Jacobs [22]  are summarized in Table 6.4.1. If the
            residence  time  required  for  coalescence  is  5.0 min, obtained  from  experiments,
            find the dimensions of the decanter.

            The volumetric flow rates of both phases are
                      1.26 kg  1   m 3
                 m L
                                               3
                                                  3
                                                            3
            V L  = —— = ————  ———— =   1.405xlO~  m /s (0.0356 ft /s)
                       1  s  897  kg
                 p L
            and


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