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Separator Design                                              295


            placed  by  an  equivalent  diameter  for  the  noncircular  flow  area.  The  equivalent
            diameter is equal to four  times the hydraulic radius, which is  defined  as the cross-
            sectional area of the stream (flow area) divided by the wetted perimeter. The defi-
            nition of hydraulic radius is only valid  for turbulent flow,  as  discussed by Bird et
            al.  [68].  For a liquid-liquid interface  located at the center of the decanter, the flow
            area is equal to  1A the cross-sectional area of the separator, and the wetted perime-
                                              1
            ter is equal to the separator diameter plus A its circumference.
            Table 6.15  Summary of Equations for Sizing Liquid-Liquid Separators

            Subscripts: L = light phase - H = heavy phase
                     D = dispersed phase -  C = continuous phase

            Transport Relations
               v 'fpL'UH'V- 30
                L
            e  =  —  I  ——  I                                          (6.15.1)



            V D = V L' or V D =V H'  —  from Table 6.13  —  V D, light or heavy phase  (6.15.2)

               VLorvD = VH —  from Table 6.13  —  VD, light or heavy phase  (6.15.3)
            VD =
               PL' or  PC =PH'  —  from Table 6.13  —  p, light or heavy phase  (6.15.4)
            PC =
                                                 c
            PD  =  PL' or p D = p H'  —  from Table 6.13  —  p D, light or heavy phase  (6.15.5)

            LL C = |i L ' or u c  =  UN'  —  from Table 6.13  —  Uc, light or heavy phase  (6.15.6)
                    2
                g(d') (p D '- Pc ')
            v d =  —————————                                           (6.15.7)
                    18 nc
            t D =  D/2v d                                              (6.15.8)

            L s =  v D t D                                             (6.15.9)

            H D = 0.1D                                                (6.15.10)

                (1/2) H D A,
            t R '= ——————                                             (6.15.11)
                  V D




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