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342                                                       Chapter 6

           is  the  same  as  the  calculation  given  above  using  only  the  feed  volatility.  Table
           6.7.3  summarizes  the results.  The new  compositions  could  be used to  generate  a
           new geometric-mean relative volatility for each component and the calculation can
           be repeated.  Further iteration is not warranted, however, considering the approxi-
           mate nature of the calculation.
                The next step in the procedure is to calculate the optimum or operating reflux
           ratio.  First,  calculate  the  minimum  reflux  ratio  using  the  Underwood  equations,
           Equations 6.27.3 and 2.21 A. For the calculation use the geometric average volatil-
           ity  of  each  component  listed  in  Table  6.27.3.  Because  the  feed  is  at  its  bubble
           point, q = 1. Thus, Equations 6.27.3 and 6.27.4 becomes

                    ViF  6.130(0.05)  2.013(0.35)  1.0(0.15)  0.8802(0.20)

               (ccDavg-9  6.130-6      2.013-6     1.0-6         0.8802-9

            0.4598(0.10)  0.3970(0.15)
           ———————     +  ——————— = o
            0.4598-9     0.3970-6

                    (oOavgXio  6.130(0.1255)  2.013(0.8695)  1.0(0.003764)
           R M  +  1 =  —————  =  ————————   +  ————————   + ————————
                    (aOavg-6     6.130-6        2.013-6       1.0-6

                                                                 7
                                              7
             0.8802 (0.001179)  0.4598 (3.583xlO~ )  0.3971 (LOlOxlO" )
                0.8802-6          0.4598-6           0.3971-9
                Solving the first  of these equations using Polymath, we find  that 6=1.297.
           Substitute  this  value  of  6  into  the  second  equation  and  solve  for R M  to  obtain
            1.589.
                Now,  calculate  the  optimum  reflux  ratio  using  Equations  6.27.5  to  6.27.7.
           From Equation 6.27.6,

                       2.013
           Y 0 = —————————————      =1.171
                1.0614 (2.013)-0.4175

           and from Equation 6.27.7,

                                                      55 2
                   T  (  0.3465  ^  (  0.1485 ^(  0.35  ^ ] °-  ( -°«>
                   L  (.  0.0015  )  I  0.0035  )  I  0.15  )\





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