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Reactor Design                                                381


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                Substitute x (A = 0, x 2A =  0.37,  V v = 5600 ft /h,  m, A = 738.7 Ibmol/h and k =
            3.766/h"1 into these equations. Then,  solve the equations using POLYMATH  [22].
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            The  reaction volume  is  873.3  ft 3  (24.7  m ),  which is  the  maximum reaction  vol-
            ume.
                The  minimum reaction volume will be  for a plug  flow  reactor, which, for a
            first  order reaction is
                       1     5600     1
               V v
                                                  3
                                                         3
            V r = —  In ——— =  ——— hi ———— = 687.0 ft  (19.5  m )
                k   l-x 2A  3.766  1-0.37
                For two CSTRs, generate a set of equations for n = 1 and  n = 2.  For the first
            CSTR,  when n =  1, the  equations  are the  same  as written above.  For  the  second
            CSTR, n = 2 in Equations  7.4.1  and 7.4.3  to 7.4.5.

            m 2A = m 3A + (x 3A -  x 2A ) m 2A


            -r 3AV r = (x 3A -x 2A )m 2A

            r 3A = - k c 3A

            c 3A =m 3A /V v
                 With x 3A =  0.37,  and using the same values of  XIA , V v , m 1A,  and k  as for
            one  CSTR,  the  eight  equations  are  solved  simultaneously  using  POLYMATH
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            [22].  For  two CSTRs, the total reaction volume is 772.9 ft  (21.9  m ) , which is in
            between the reaction volumes of a single CSTR (873.3  ft3)  (24.7  m3)  and the plug
            flow  reactor (687.0  ft3)  (19.5  m3).  The  difference  in reaction volume between one
            and two CSTRs is only  1 1.5 %, which is not substantial. Select a single CSTR.
                 The next  step is to  select a standard  CSTR. For the  calculated reaction  vol-
                                       3
            ume of 873.3 ft 3  (6533  gal,  24.7  m ),  select a standard reaction volume from Table
            7.3  of  8000  gal  (30.3  m3).  Also,  from  Table  7.3  the  reactor  volume  is  8765  gal
                  3
            (33.2  m )  to  allow  for headspace.  Now,  we have  a number  of  options  available.
            One option is not to  fill  the  standard reactor up to the rated volume but only up to
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            the  calculated reaction volume of 6533 gal  (24.7  m )  and maintain the volumetric
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            flow rate  at 5600 ft /h  (21.2  m /h). This means that the  conversion will be  0.37  as
            specified.  CSTRs have  a minimum operating reaction volume  to  avoid  imperfect
            mixing.  Mixing  depends  on  the  properties  of  the  reaction  mixture,  the  impeller
            design  and  speed,  and  the  internal  design  of the  CSTR.  The  minimum operating
            reaction  volume  for  good  mixing  should  be  determined  by  consulting  with  the
            manufacturer  of  the  CSTR. A  second  option  is to  fill  the  reactor  up  to  8000  gal
            (30.3  m3)  and  increase  the  volumetric  flow  rate  to  keep  the  residence  time  and
            therefore  the  conversion constant. A third  option is  to  again  fill  the reactor up  to





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