Page 85 - Civil Engineering Formulas
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40                      CHAPTER TWO

                                          W


                         L 1      L 2      L 3      L 4

                    R 0      R 1      R 2      R 3      R 4
                                      (a)




                                                 d 3
                              d 1         d 2
                                      (b)
                              1


                                               y 31
                             y 11     y 21
                                      (c)
                                       1



                                                 y
                              y 12      y 22     32
                                      (d)
                                                1



                              y 13
                                       y 23      y 33
                                      (e)

                            d = y R + y R + y R
                                            13 3
                                      12 2
                                11 1
                             1
                            d = y R + y R + y R
                                            23 3
                             2
                                      22 2
                                21 1
                            d = y R + y R + y R
                                31 1
                                            33 3
                             3
                                      32 2
                 FIGURE 2.5  Reactions of continuous beam (a) found by making
                 the beam statically determinate. (b) Deflections computed with inte-
                 rior supports removed. (c), (d), and (e) Deflections calculated for
                 unit load over each removed support, to obtain equations for each
                 redundant.
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