Page 85 - Civil Engineering Formulas
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40 CHAPTER TWO
W
L 1 L 2 L 3 L 4
R 0 R 1 R 2 R 3 R 4
(a)
d 3
d 1 d 2
(b)
1
y 31
y 11 y 21
(c)
1
y
y 12 y 22 32
(d)
1
y 13
y 23 y 33
(e)
d = y R + y R + y R
13 3
12 2
11 1
1
d = y R + y R + y R
23 3
2
22 2
21 1
d = y R + y R + y R
31 1
33 3
3
32 2
FIGURE 2.5 Reactions of continuous beam (a) found by making
the beam statically determinate. (b) Deflections computed with inte-
rior supports removed. (c), (d), and (e) Deflections calculated for
unit load over each removed support, to obtain equations for each
redundant.