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A Variational Inequality Theory Chapter | 4 95


                           and

                                                 T                 T
                                               M (D( )) =       {M x}.
                                                           x∈D( )
                                                            T
                           Condition (4.60) means that if q ∈ M (D( )) + R + (M,  ∞ ), then q ∈
                           R(M, ).
                              ii) Note that if B(M, ) ={0} (see also Corollary 6), then condition (4.60)
                           is trivially satisfied on the empty set.
                           Remark 27. If 0 ∈ D( ) (which is the case for most practical problems), then
                           we may choose x 0 = 0to see (4.60) in the more legible form

                                         (∀v ∈ B(M, ),v 
= 0) : q,v +   ∞ (v) > 0.    (4.62)

                              Theorem 8 may be applied to the class of positive semidefinite matrices, that
                           is,
                                                       n
                                                 (∀x ∈ R ) : Mx,x ≥ 0.
                           This last class of (not necessarily symmetric) matrices is of particular interest
                           for various problems in engineering, and it is then worthwhile to specify our
                           results in this framework.

                                              n
                           Corollary 7. Let   : R → R ∪{+∞} be a proper convex lower semicontinu-
                           ous function with closed domain, and let M ∈ R n×n  be a positive semidefinite
                           matrix.
                                                                                  n
                                                 T
                            a) If D( ) ∞ ∩ ker(M + M ) ∩ K(M, ) ={0}, then for each q ∈ R , problem
                              VI(M,q, ) has at least one solution.
                                                           T
                            b) Suppose that D( ) ∞ ∩ ker(M + M ) ∩ K(M, ) 
= {0}. If there exists x 0 ∈
                              D( ) such that
                                                               T
                                        (∀v ∈ D( ) ∞ ∩ ker(M + M ) ∩ K(M, ), v 
= 0)
                              and
                                                      T
                                                 q − M x 0 ,v +   ∞ (v) > 0,          (4.63)
                              then problem VI(M,q, ) has at least one solution.
                            c) If u 1 and u 2 are two solutions of problem VI(M,q, ), then
                                                                    T
                                                  u 1 − u 2 ∈ ker(M + M ).            (4.64)
                                                                      n
                                                      T
                           Proof. Setting X 1 = ker(M + M ), we may write R = X 1 ⊕ X . We denote
                                                                                ⊥
                                                                                1
                                                                     n
                                  (resp. P  ⊥) the orthogonal projector from R onto X 1 (resp. X ). The
                                                                                    ⊥
                                        X                                           1
                           by P X 1
                                         1
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