Page 312 - Corrosion Engineering Principles and Practice
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282   C h a p t e r   8                                 C o r r o s i o n   b y   W a t e r    283


                      Calculation  Example.  For  this  problem,  imagine  a  situation  where
                      you would have to design a sacrificial CP system for the protection of
                      the  four  main  pillars  of  an  oil-drilling  platform.  These  pillars  are
                      basically sealed steel cylinders, 1 m in diameter and 25 m long in their
                      immerged section. The sacrificial anodes are zinc bars 100 cm long, 12
                      cm wide and 12 cm thick, with their back tightly screwed onto the
                      steel surface. This problem is a particular application of the blocking
                      or passivation of an electrode surface by forcing the accumulation of
                      some ions that can eventually precipitate and block the surface.
                         Answer the following questions knowing that the temperature of
                      the seawater decreases exponentially as a function of depth, changing
                      from 25°C at the surface to 10°C at a depth of 25 m and that the diffusion
                      coefficient of CO  can be described by the following expression:
                                    2−
                                   3
                                     D =  D   (1 −  0.043 ×  (25 −  t))    (8.16)
                                      t    25 C
                                            o
                      where D  is the diffusion coefficient of CO  at temperature t
                                                          2−
                             t
                                                         3
                            t is the temperature in °C
                            D   is the diffusion coefficient of CO  at 25°C (5 × 10  cm  s )
                                                          2−
                                                                             −1
                                                                       −5
                             25°C                         3                 2
                        Question 1:  Given that the corrosion rate of unprotected steel is 1.1 mm y ,
                                                                              −1
                        estimate the total corrosion current for one pillar.
                        Answer
                        Surface area of one pillar = p  × diameter × length = 3.1416 × 1 × 25 m 2
                        Surface area of one pillar = 78.54 m 2
                        Corrosion current = surface area × corrosion rate in current density units
                                  −1
                                              −2
                        Since 1 mm y   = 0.0863 mA cm  or 0.863 A m −2
                        Corrosion current = 1.1 × 0.863 × 78.54 = 74.56 A
                        Question  2:  Given  that  the  zinc  anodes  can  provide  a  sacrificial  current
                        corresponding to a corrosion rate of zinc of 7 mm y  , evaluate the number of
                                                             −1
                        anodes that would be required to reduce the corrosion of steel by a factor of ten.
                        Assume that the total corrosion current calculated in Question 1 remains the
                        same to balance a constant cathodic process, the reduction of oxygen.
                        Answer
                        Surface of each anode = face + sides + ends
                        Surface of each anode = (12 × 100) + 2 × (12 × 100) + 2 × (12 × 12) = 3888 cm
                                                                            2
                        Conversion of corrosion rate into current units: 1 mm y   = n × density × 0.306/M
                                                             −1
                        For zinc, n = 2, density = 7.133 g cm , M = 65.38 g mol −1
                                                 −3
                        Corrosion current density of anode = 7 × 2 × 7.133 × 0.306/65.38 = 0.4674 mA cm −2
                        Corrosion current/anode = 0.4574 × 3888 = 1.817 A
                        The  current  required  is  90  percent  of  the  current  calculated  in  Question  1
                        or 0.9 × 74.56 A, that is, 67.1 A
                        Number of anodes required = 67.1/1.817 = 36.9 anodes
                        Question 3:  In order to reduce the consumption of anodes over time you would
                        like to force the precipitation of calcareous deposits onto your steel surface
                        because you know that by doing so you can cut down the corrosion of steel a
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