Page 108 - Design and Operation of Heat Exchangers and their Networks
P. 108

96    Design and operation of heat exchangers and their networks


             As is shown in Fig. 3.6A, a two-pass cross counterflow heat exchanger
          can be coupled with two crossflow units in a counterflow scheme, in which
          fluid 1 first enters unit A (the first pass of fluid 1) and then enters unit B (the
          second pass of fluid 1), but fluid 2 first enters unit B and then flows from unit
          B to unit A. If each fluid is mixed in one of its two passes or in its interpass,
                                  ∗
                                        ∗
          the interpass temperatures, t 1 and t 2 , and the outlet temperature of fluid 1 of
                         00
          the exchanger, t 1 , can be expressed with the dimensionless temperature
          changes of fluid 1 in unit A and unit B, ε 1,A and ε 1,B , which are defined
          by Eq. (3.60):
                                 ∗
                                        ∗
                                t  ε 1,A t ¼ 1 ε 1,A Þt 0 1          (3.145)
                                           ð
                                 1
                                        2
                                             ∗
                                 00
                                t   1 ε 1,B Þt ¼ ε 1,B t 0           (3.146)
                                    ð
                                 1           1      2
             The ε-NTU relationships for the crossflow with both fluids unmixed,
          with one fluid unmixed and the other mixed, and with both fluids mixed
          are given by Eqs. (3.122), (3.134) (or (3.135)), (3.144), respectively.
             According to the energy balance, we also have
                                               ∗
                                           ∗
                                     00
                                  R 1 t  R 1 t + t ¼ t 0             (3.147)
                                     1     1   2   2
                                                      ∗
                                                             ∗
                                                    00
             Solving Eqs. (3.145)–(3.147) for unknown t 1 , t 1 , and t 2 results in
                                 ∗
                                 t  t  0   1 ε 1,A
                                 1   2
                                      ¼                              (3.148)
                                 t  t  0  1 R 1 ε 1,A ε 1,B
                                 0
                                 1   2
                                 ∗
                                t  t 0  R 1 ε 1,B  ε 1,A Þ
                                          ð
                                 2   2
                                      ¼                              (3.149)
                                t  t 0
                                 0
                                 1   2  1 R 1 ε 1,A ε 1,B
                            t  t 1 00  ε 1,A + ε 1,B   1+ R 1 Þε 1,A ε 1,B
                             0
                                               ð
                             1
                        ε 1 ¼     ¼                                  (3.150)
                            t  t 0
                             0
                             1   2        1 R 1 ε 1,A ε 1,B
             The dimensionless temperatures in a parallel-crossflow heat exchanger
          can be obtained with the similar method as follows, if each fluid is mixed
          in one of its two passes or in its interpass:
                                    ∗
                                   t  t 0 2
                                    1
                                         ¼ 1 ε 1,A                   (3.151)
                                    0
                                   t  t 0
                                    1   2
                                     ∗
                                    t  t 0
                                    2   2
                                         ¼ R 1 ε 1,A                 (3.152)
                                     0
                                    t  t 0
                                    1   2
                            t  t  00
                             0
                                               ð
                        ε 1 ¼  1  1  ¼ ε 1,A + ε 1,B   1+ R 1 Þε 1,A ε 1,B  (3.153)
                            t  t 0 2
                             0
                             1
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