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Basic thermal design theory for heat exchangers  61


              with

                                     64=Re,         Re < Re cr
                              f D,s ¼          0:25                     (2.155)
                                     0:3164=Re    ,Re > Re cr

                                                       0:45
                                 Re cr ¼ 2300 1 + 8:6 r=r c Þ           (2.156)
                                                   ð
                 For two-phase frictional pressure drop, Colombo et al. (2015) proposed a
              correlation,inwhichcorrectiveparametersareincludedintothetwo-phasemul-
              tiplierofLockhartandMartinellitoaccountfortheeffectofthecentrifugalforce:
                                          2
                                 2
                                ϕ ¼ 0:13ϕ De  0:15 ð ρ =ρ Þ  0:37       (2.157)
                                 l        l,s  l   m  l
              where
                                       h               i  1
                                  ρ ¼ _x=ρ +1  _xÞ=ρ                    (2.158)
                                              ð
                                   m       g          l
                  2
                 ϕ l,s is the two-phase multiplier for straight tube, calculated from
              Eq. (2.151) with C¼20 for turbulent flow of both liquid and vapor phases
              and the Lockhart-Martinelli parameter X as
                                                      !   0:1
                                               ρ
                                           0:9
                                                   0:5
                                     1  _x      g     μ l
                                X ¼                                     (2.159)
                                       _ x     ρ      μ
                                                l      g
              2.2.2 Static pressure drop
              The static pressure drop (hydrostatic pressure) is the difference in pressure at
              two points within a fluid column, due to the weight of the fluid:

                                       Δp g ¼ ρ gΔH                     (2.160)
                                              m
              in which g is acceleration due to gravity, H the elevation, and ρ m the mean
              density of the fluid column.
                 In a pipe flow, the static pressure drop can be expressed as.

                                       dp g ¼ ρ gsinθdz                 (2.161)
              where θ denotes the angle of inclination of the tube. For upward flow, θ>0;
              therefore, the static pressure drop is positive. For downward flow, the static
              pressure drop is negative. ρ is the local fluid density.
                 The total static pressure drop can be calculated by integration of the local
              pressure drop gradient over the whole pipe length:
                                            Z
                                              L
                                     Δp g ¼ g  ρsinθdz                  (2.162)
                                             0
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