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A.4 Appell Polynomials  317

          Appell Sets
          Any sequence of polynomials {φ m (x)} where φ m (x) is of exact degree m
          and satisfies the Appell equation (A.4.5) is known as an Appell set.
            The sequence in which
                                     −1

                              m + s
                    φ m (x)=           (x + c) m+s ,  s =1, 2, 3,...,
                                s
          satisfies (A.4.5), but its members are not of degree m. The sequence in
          which
                                2 2m+1 m!(m + 1)! (x + c) m+(1/2)
                        φ m (x)=
                                          (2m + 2)!
          satisfies (A.4.5), but its members are not polynomials. Hence, neither
          sequence is an Appell set.
            Carlson proved that if {φ m } and {ψ m } are each Appell sets and
                                       m
                                           m
                             θ m =2 −m         φ r ψ m−r ,
                                            r
                                      r=0
          then {θ m } is also an Appell set.
            In a paper on determinants with hypergeometric elements, Burchnall
          proved that if {φ m } and {ψ m } are each Appell sets and

                                   n
                          n

                    θ m =   (−1) r     φ m+n−r ψ r ,  n =0, 1, 2,...,
                                    r
                          r=0
          then {θ m } is also an Appell set for each value of n. Burchnall’s formula can
          be expressed in the form

                         n


                   θ m =   (−1)  r    ψ r  φ m+n−r    ,  n =0, 1, 2,... .
                                 ψ r+1  φ m+n−r+1

                        r=0
          The generalized Appell equation

                              θ    = mf θ m−1 ,  f = f(x),
                               m
          is satisfied by
                                    θ m = φ m (f),
          where φ m (x) is any solution of (A.4.5). For example, the equation
                                         mθ m−1
                                    θ    =
                                         (1 + x)
                                     m         2
          is satisfied by
                                              1

                                 θ m = φ m −       .
                                            1+ x
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