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336   Appendix

          This solution can be particularized still further using Cauchy’s theorem.
          First, allow C to embrace α but not β and then allow C to embrace β but
          not α. This yields the solutions

                                 ρ −1−r     −ρ −1−r
                                        ,           ,
                               β (α − β)   α (α − β)
                                             r
                                 r
          but since the coupled equations are linear, the difference between these two
          solutions is also a solution. This solution is
                            ρ −1−r (α + β )  (−1) f r (z/ρ)
                                   r
                                       r
                                                r
                                                        ,          (A.11.6)
                             (αβ) (α − β)      1+ z /ρ 2
                                          = +
                                                   2
                                 r
          where
                                +               +        .
                         1
                          -
                  f n (x)=  (x +  1+ x ) +(x −    1+ x )  .        (A.11.7)
                                      2 n
                                                       2 n
                         2
          Since z does not appear in the coupled equations except as a differential
          operator, another particular solution is obtained by replacing z by z + c j ,
          where c j is an arbitrary constant. Denote this solution by u rj :
                                (−1) f r (x j )
                                     r
                           u rj =  3       ,  x j =  z + c j  .    (A.11.8)
                                    1+ x 2           ρ
                                        j
          Finally, a linear combination of these solutions, namely
                                         2n

                                   u r =   e j u rj ,              (A.11.9)
                                        j=1
          where the e j are arbitrary constants, can be taken as a more general series
          solution of the coupled equations.
            A highly specialized series solution of (A.11.1) and (A.11.2) can be ob-
          tained by replacing r by (r−1) in (A.11.1) and then eliminating u r−1 using
          (A.11.2). The result is the equation

                      2              2          2
                    ∂ u r
                         −  1 ∂u r  −  (r − 1)u r  +  ∂ u r  =0,  (A.11.10)
                     ∂ρ 2  ρ ∂ρ        ρ 2      ∂z 2
          which is satisfied by the function


                     u r = ρ  {a n J r (nρ)+ b n Y r (nρ)}e ±nz ,  (A.11.11)
                            n
          where J r and Y r are Bessel functions of order r and the coefficients a n and
          b n are arbitrary. This solution is not applied in the text.
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