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3.3 The Laplace Expansion  31

          The retainer minor is signless and equal to R. The sign of the cofactor is
          (−1) , where
              k
                                   n
                                                 2
                              k =    (n +2r)=2n + n.
                                  r=1
          Hence, the cofactor is equal to (−1) Q. Part (b) of the lemma follows.
                                        n
            Similar arguments can be applied to more general determinants. Let X pq ,

          Y pq , Z pq , and O pq denote matrices with p rows and q columns, where O pq
          is null and let


                                 A n =     X pq  Y ps    ,          (3.3.14)
                                         O rq  Z rs
                                                 n
          where p + r = q + s = n. The restriction p ≥ q, which implies r ≤ s, can
          be imposed without loss of generality. If A n is expanded by the Laplace
          method taking minors from the first q columns or the last r rows, some
          of the minors are zero. Let U m and V m denote determinants of order m.
          Then, A n has the following properties:
          a. If r + q> n, then A n =0.
          b. If r + q = n, then p + s = n, q = p, s = r, and A n = X pp Z rr .
          c. If r + q< n, then, in general,

                  A n = sum of  p
                               q  nonzero products each of the form U q V s

                     = sum of  s  nonzero products each of the form U r V r .
                               r
          Property (a) is applied in the following examples.
          Example 3.2. If r + s = n, then


                           U 2n =     E n,2r  F ns  O ns    =0.

                                  E n,2r
                                         O ns
                                              F ns
                                                   2n
          Proof. It is clearly possible to perform n row operations in a single step
          and s column operations in a single step. Regard U 2n as having two “rows”
          and three “columns” and perform the operations
                                   R = R 1 − R 2 ,

                                     1

                                   C = C 2 + C 3 .
                                     2
          The result is


                            U 2n =     O n,2r  F ns  −F ns

                                                 F ns
                                          O ns
                                   E n,2r
                                                     2n


                                =     O n,2r  O ns  −F ns

                                                 F ns
                                          F ns
                                   E n,2r
                                                     2n
                                =0
          since the last determinant contains an n × (2r + s) block of zero elements
          and n +2r + s> 2n.
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