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3.4 Double-Sum Relations for Scaled Cofactors  35

          A and (A ) and the other two are identities:

                   ij
                            A
                                           n
                                               n
                               = (log A) =       a A ,                 (A)


                                                     rs
                             A                    rs
                                           r=1 s=1
                                        n  n

                               ij
                             (A ) = −        a A A ,                   (B)
                                                  is
                                                     rj
                                              rs
                                       r=1 s=1
                          n   n                  n

                                (f r + g s )a rs A rs  =  (f r + g r ),  (C)
                         r=1 s=1                r=1
                         n  n

                              (f r + g s )a rs A A rj  =(f i + g j )A .  (D)
                                                          ij
                                          is
                        r=1 s=1
          Proof. (A) follows immediately from the formula for A in terms of un-

          scaled cofactors in Section 2.3.7. The sum formula given in Section 2.3.4
          can be expressed in the form
                                    n

                                      a rs A = δ ri ,                (3.4.1)
                                          is
                                   s=1
          which, when differentiated, gives rise to only two terms:
                               n            n

                                     is            is
                                 a A = −      a rs (A ) .            (3.4.2)
                                  rs
                              s=1          s=1
          Hence, beginning with the right side of (B),
                        n   n


                              a A A  rj  =  A rj   a A is

                                  is
                               rs                   rs
                       r=1 s=1            r      s

                                                          is
                                       = −    A rj   a rs (A )
                                            r      s

                                                is
                                       = −    (A )     a rs A rj
                                            s       r

                                                is
                                       = −    (A ) δ sj
                                            s
                                       = −(A )
                                             ij
          which proves (B).

                          (f r + g s )a rs A A rj
                                      is
                     r  s

                        =     f r A rj  a rs A +  g s A is  a rs A rj
                                           is
                            r        s          s       r
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