Page 52 - Determinants and Their Applications in Mathematical Physics
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3.5 The Adjoint Determinant  37
          Proof.


                                 A adj A = |a ij | n |A ji | n
                                       = |b ij | n ,
          where, referring to Section 3.3.5 on the product of two determinants,

                                         n

                                   b ij =  a ir A jr
                                        r=1
                                      = δ ij A.
          Hence,

                               |b ij | n = diag|A A ... A| n
                                    = A .
                                       n
          The theorem follows immediately if A  =0. If A = 0, then, applying (2.3.16)
          with a change in notation, |A ij | n = 0, that is, adj A = 0. Hence, the Cauchy
          identity is valid for all A.


          3.5.3  An Identity Involving a Hybrid Determinant
          Let A n = |a ij | n and B n = |b ij | n , and let H ij denote the hybrid determinant
          formed by replacing the jth row of A n by the ith row of B n . Then,
                                         n

                                   H ij =  b is A js .               (3.5.2)
                                        s=1
          Theorem.


                      |a ij x i + b ij | n = A n   ij x i +  H ij     ,  A n  =0.
                                        δ


                                               A n n
          In the determinant on the right, the x i appear only in the principal diagonal.
          Proof. Applying the Cauchy identity in the form
                                    |A ji | n = A n−1
                                             n
          and the formula for the product of two determinants (Section 1.4),
                         |a ij x i + b ij | n A n−1
                                     n   = |a ij x i + b ij | n |A ji | n
                                         = |c ij | n ,
          where
                                  n

                             c ij =  (a is x i + b is )A js
                                 s=1
                                     n          n

                                       a is A js +  b is A js
                               = x i
                                    s=1        s=1
                               = δ ij A n x i + H ij .
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