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0593_C07_fm  Page 204  Monday, May 6, 2002  2:42 PM





                       204                                                 Dynamics of Mechanical Systems


                                             D = d  n n + d  n n + d  n n
                                                  11 1 1  12  1  2  13  1  3
                                                   + d  nn + d  nn + d  nn                      (7.4.6)
                                                  21  2  1  22  2  2  23  2  3
                                                   + d  nn + d  nn + d  nn = d  n n
                                                  31  3  1  22  3  2  33  3  3  ij  i  j

                       Observe that a dyadic may be thought of as being a vector whose components are vectors;
                       hence, dyadics are sometimes called vector–vectors. Observe further that the scalar com-
                       ponents of D (the d  of Eq. (7.4.6)) can be considered as the elements of a 3 × 3 matrix and
                                        ij
                       as the components of a second-order tensor (see References 7.5, 7.6, and 7.7).
                        In Eq. (7.3.12), we see that the moments and products of inertia may be assembled as
                       elements of a matrix. In Eq. (7.4.3) these elements are seen to be I  (i, j = 1, 2, 3). If these
                                                                                 ij
                       matrix elements are identified with dyadic components, we obtain the inertia dyadic
                       defined as:

                                                    =
                                                I PO D  I  n n +  I  n n +  I  n n
                                                        11 1 1  12  1  2  13  1  3
                                                     +  I  nn +  I  nn +  I  nn                 (7.4.7)
                                                       21  2  1  22  2  2  23  2  3
                                                     +  I  nn +  I  nn +  I  nn
                                                       31  3  1  32  3  2  33  3  3

                       or

                                                         I  PO  =  I  n n                       (7.4.8)
                                                               ij  i  j

                       By comparing Eqs. (7.4.2) and (7.4.7), we see that the inertia dyadic may also be expressed
                       in the form:


                                                  I  PO  =  n I PO +  n I  PO  +  n I PO        (7.4.9)
                                                         1 1    22     33
                        Equation (7.3.5) shows that the matrix of moments and products of inertia is symmetric
                       (that is, I  = I ). Then, by rearranging the terms of Eq. (7.4.7), we see that I P/O  may also be
                              ij
                                  ji
                       expressed as:
                                                  I  PO  =  I  PO n + I  PO n +  I PO n        (7.4.10)
                                                        1   1  2   2  3   3
                       The inertia dyadic may thus be interpreted as a vector whose components are second-
                       moment vectors.
                        A principal advantage of using the inertia dyadic is that it can be used to generate
                       second-moment vectors, moments of inertia, and products of inertia. Specifically, once the
                       inertia dyadic is known, these other quantities may be obtained simply by dot product
                       multiplication with unit vectors. That is,


                                                               ⋅
                                                I  PO  =  I  PO  n ⋅  =  n I  PO  i = (  12  ) 3  (7.4.11)
                                                                        ,,
                                                 i         i   i
                       and

                                                          ⋅
                                                   I PO  =  n I PO  n ⋅  i = (  12  ) 3        (7.4.12)
                                                                      ,,
                                                   ij    i      j
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