Page 152 - Electrical Installation in Hazardous Area
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1 18 Electrical installations in hazardous areas
4.3.1 Example of liquid release above its atmospheric boiling point
Example 5
Liquid propylene is contained in a vessel at a temperature of 15°C and
a pressure equal to its own vapour pressure at that temperature. It leaks
down a drain line of 0.019 m bore (2.8 x m2 area) and 0.3 m length.
Basic information is as follows:-
Storage pressure (vapour pressure) 8.94 x 105N/m2
Process temperature 288 K
Material boiling point 225 K
Temperature to give P, 267 K
Latent heat of vaporization 469 kj / kg
Heat capacity of liquid at 288K 2.26 kj / kg /K
Liquid density 520 kg/m3
Vapour density 9.43 kg/m3
Molecular weight 42
Lower explosive limit 2% in air
Due to the relationship between the drain length and its bore vaporiza-
tion will take place within the leak path and thus the fluid leaking will be
a mixture of vapour and liquid. In such cases it is necessary to calculate a
density for the mixture and the first step is to calculate the amount vapor-
izing in the leak path. From Equation 4.29 the fraction vaporizing in the
leak path as a percentage of leakage is given by:
M, = (288 - 267)2.26/469
M, = 0.1
Using this fraction the density of the mixture can now be calculated using
Equation 4.30 as follows:
a, = 1/[(0.1/9.43) + (0.9/520)] kg/m3
0, = 81.3 kg/m3
The fraction of release flashing-off as vapour inside the release orifice and
outside at the point of release is given by Equation 4.27 and this gives the
following:
= (288 - 225)2.26/469 kg/s
We can now calculate the mass release using this density figure in Equa-
tion 4.28 as follows:
G = 0.8 x 2.8 x 10-~[2 x 81.q8.94 x io5 - 4.92 x 105)]0.5 kg/s
G = 1.81 kg/s
Of this there will be some which appears at the outside of the orifice as
vapour and some which will flash-off in the immediate locality of the orifice

