Page 368 - Electromagnetics
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To obtain a formula for V l we take the divergence of (5.9) and use (5.11) to get
                                                                         2
                                                ∇· V =∇ · V l =∇ · ∇φ =∇ φ.
                        The result,
                                                          2
                                                        ∇ φ =∇ · V,
                        may be regarded as Poisson’s equation for the unknown φ. This equation is solved in
                        Chapter 3. By (3.61) we have
                                                              ∇ · V(r )


                                                  φ(r) =−             dV ,
                                                            V  4π R

                        where R =|r − r |, and we have
                                                               ∇ · V(r )


                                                 V l (r) =−∇           dV .                    (5.12)
                                                             V   4π R
                        Similarly, a formula for V s can be obtained by taking the curl of (5.9) to get
                                                       ∇× V =∇ × V s .
                        Substituting (5.10) we have
                                                                             2
                                            ∇× V =∇ × (∇× A) =∇(∇· A) −∇ A.
                        We may choose any value we wish for ∇· A, since this does not alter V s =∇ × A.
                        (We discuss such “gauge transformations” in greater detail later in this chapter.) With
                        ∇· A = 0 we obtain
                                                                  2
                                                       −∇ × V =∇ A.
                        This is Poisson’s equation for each rectangular component of A; therefore

                                                            ∇ × V(r )

                                                   A(r) =            dV ,
                                                          V    4π R
                        and we have
                                                               ∇ × V(r )


                                                 V s (r) =∇ ×           dV .
                                                             V   4π R
                        Summing the results we obtain the Helmholtz decomposition





                                                       ∇ · V(r )            ∇ × V(r )

                                   V = V l + V s =−∇           dV +∇ ×               dV .      (5.13)
                                                     V   4π R             V   4π R
                        Identification of the electromagnetic potentials.  Let us write the electromagnetic
                        fields as a general superposition of solenoidal and lamellar components:
                                                     E =∇ × A E +∇φ E ,                        (5.14)
                                                     B =∇ × A B +∇φ B .                        (5.15)
                        One possible form of the potentials A E , A B , φ E , and φ B appears in (5.13). However,
                        because E and B are related by Maxwell’s equations, the potentials should be related to
                        the sources. We can determine the explicit relationship by substituting (5.14) and (5.15)




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