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Figure 6.1: Geometry used to derive the Stratton–Chu formula.


                                                          ˜
                                       ˜
                                  ˜
                                                                ˜
                                             ˜
                                                  ˜
                        We also let E a = E and H a = H, where E and H are the fields produced by the impressed
                               ˜
                                          ˜
                                               ˜ i
                                   ˜ i
                        sources J a = J and J ma = J within V that we wish to find at r = r p . Since the dipole
                                                m
                        fields are singular at r = r p , we must exclude the point r p with a small spherical surface
                        S δ surrounding the volume V δ as shown in Figure 6.1. Substituting these fields into (6.2)
                        we obtain

                                         ˜   ˜    ˜    ˜                ˜   ˜ i  ˜  ˜ i

                                  −      E × H p − E p × H · ˆ n dS =   E p · J − H p · J  dV .  (6.5)
                                                                                     m
                                     S+S δ                         V −V δ
                          A useful identity involves the spatially-constant vector ˜ p and the Green’s function
                        G(r |r p ):

                                                                             2
                                           ∇ × ∇ × (G ˜ p) =∇ [∇ · (G ˜ p)] −∇ (G ˜ p)




                                                                              2


                                                          =∇ [∇ · (G ˜ p)] − ˜ p∇ G
                                                                           2


                                                          =∇ (˜ p ·∇ G) + ˜ pk G,               (6.6)
                                                   2
                                            2
                        where we have used ∇ G =−k G for r  = r p .

                          We begin by computing the terms on the left side of (6.5). We suppress the r de-

                        pendence of the fields and also the dependencies of G(r |r p ). Substituting from (6.3) we

                        have

                                               ˜
                                           ˜
                                                                   ˜






                                          [E × H p ] · ˆ n dS = jω    E ×∇ × (G ˜ p) · ˆ n dS .
                                       S+S δ                  S+S δ
                                 ˜
                                                                         ˜
                                                     ˜
                        Using ˆ n · [E ×∇ × (G ˜ p)] = ˆ n · [E × (∇ G × ˜ p)] = (ˆ n × E) · (∇ G × ˜ p) we can write







                                            ˜   ˜                         ˜
                                           [E × H p ] · ˆ n dS = jω˜ p ·  [ˆ n × E] ×∇ GdS .
                                        S+S δ                     S+S δ
                        © 2001 by CRC Press LLC
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