Page 160 -
P. 160

z  = 1 + 2j and z  = 2 + j
                                                                   2
                                                   1
                             Solution: Grouping the real and imaginary parts separately, we obtain:

                                                         z  + z  = + 3j
                                                         1
                                                             2
                             and

                                                        z  – z  = –1 + j
                                                         1  2


                             Preparatory Exercise

                             Pb. 6.1 Given the complex numbers z , z , and z  corresponding to the ver-
                                                                        3
                                                               1
                                                                  2
                             tices P , P , and P  of a parallelogram, find z  corresponding to the fourth ver-
                                  1
                                     2
                                                                   4
                                            3
                             tex P . (Assume that P  and P  are opposite vertices of the parallelogram).
                                                        2
                                                 4
                                 4
                             Verify your answer graphically for the case:
                                               z =+   j,  z = +  j 2 ,  z = +  j 3
                                                                        4
                                                   2
                                                             1
                                                1         2          3
                             6.2.2  Multiplication by a Real or Imaginary Number
                             If we multiply the complex number z = a + jb by a real number k, the resultant
                             complex number is given by:
                                                      z
                                                         k
                                                   k ×= × ( a +  jb =)  ka +  jkb           (6.5)
                             What happens when we multiply by j?
                              Let us, for a moment, return to Example 6.1. We note the following proper-
                             ties for the three points P , P , and P :
                                                            3
                                                   1
                                                      2
                                1. The three points are equally distant from the origin of the axis.
                                2. The point  P  is obtained from the point  P  by a  π/2 counter-
                                                                           1
                                              2
                                   clockwise rotation.
                                3. The point  P  is obtained from the point P  through another  π/2
                                             3
                                                                         2
                                   counterclockwise rotation.
                              We also note, by examining the algebraic forms of z , z , z  that:
                                                                            1
                                                                              2
                                                                                 3
                                               z =  jz  and  z =  jz =  j z = − z
                                                                      2
                                                2    1        3   2     1    1

                             © 2001 by CRC Press LLC
   155   156   157   158   159   160   161   162   163   164   165