Page 18 - Bruno Linder Elementary Physical Chemistry
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August 18, 2010 11:35      9in x 6in     b985-ch01     Elementary Physical Chemistry





                                              State of Matter. Properties of Gases          3

                            Other (non-SI) units frequently used are:

                            • Pressure: mmHg or Torr (1 Torr = 133.3Pa) or atm (1 atm =
                                                                    5
                               760 mmHg) or 101.325kPa bar (1 bar = 10 Pa)
                            • Energy: electron volt, eV (1 eV = 1.602 × 10 −19  J)


                            Equation of state is an algebraic relation between pressure, volume,
                            temperature and quantity of substance.


                            1.4. Ideal or Perfect Gas Law


                                                       PV = nRT
                            This Law comprises three different Laws that preceded it.

                            1) Holding constant n and T gives PV = const or

                                                   P 1 V 1 = P 2V 2        Boyle’s Law  (1.1)
                            2) Holding constant P and n gives V/T = const or

                                                 V 1 /T 1 = V 2 /T 2      Charles’ Law  (1.2)

                            3) Holding constant P and T gives V/n = const or

                                                V 1 /n 1 = V 2 /n 2     Avogadro’s Law  (1.3)

                            1.5. Evaluation of the Gas Constant, R
                            The gas constant can be expressed in various units, all having the dimension
                            of energy per degree per mol.

                            a) R is most easily calculated from the fact that the hypothetical volume
                               of an ideal gas is 22.414L at STP (273.1 K and 1 atm). Accordingly,

                                                                  −1
                                            R = (1 atm)(22.414 L mol  )/(273.16 K)
                                              =0.08206 atmL K −1 mol −1                 (1.4)

                                          3
                            b) If V is in cm ,
                                                               3
                                           R = (1 atm)(22, 414 cm mol −1 )/(273.16 K)
                                                          3
                                             =82.06 atmcm K  −1  mol −1                 (1.5)
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