Page 198 - Elements of Chemical Reaction Engineering 3rd Edition
P. 198

170                                    Isothermal Reactor Design   Chap. 4


                         (4-39) make use of  L and not L'. Thus, one does not need to adjust these for-
                         mulas to treat spherical reactors that have different amounts of  empty space at
                         the entrance and exit (i.e.,  L # L'). Only the upper limit of  integration needs
                         to be changed, zf  = L + L' .

                           Example  4-8  Dehydrogenation Reactions in a Spherical Reactor

                           Reforming reactors  are  used  to  increase the  octane  number  of  petroleum.  In  a
                           reforming process 20,000 barrels of petroleum are to be processed per day. The cor-
                           responding mass and molar feed rates are 44 kg/s and 440 molls, respectively. In the
                           reformer, dehydrogenation reactions such as
                                                   paraffin + olefin -k H,

                           occur. The reaction is first-order in paraffin. Assume that pure paraffin enters the reac-
                           tor at a pressure of  2000 kPa and a corresponding concentration of  0.32 mol/dm3.
                           Compare the pressure'drop and conversion when this reaction is carried out in a tubu-
                           lar packed bed 2.4 m in diameter and 25  m in length with that of a spherical packed
                           bed 6 m in diameter. The catalyst weight is the same in each reactor, 173,870 kg.
                                       -Ti  = k' CA
                                       -TA=  pB(-Ti)  = pc(l-$)(-?$.)   = pc(l-$)k'C~

                           Additional information:
                                       po = 0.032 kg/dm3
                                       D,  = 0.02 dm                       = 0.4
                                       kt  = 0.02 dm3kg cat .   I.'. = 1.5 x   kg/dm.s
                                       L = L'  = 27 dm             pc = 2.6 kg/dm3

                           Solution
                           We  begin by  performing a mole balance over the cylindrical core of  thickness  Az
                           shown in Figure E4-8.1.





















                                                Figure E4-8.1  Spherical reactor.
   193   194   195   196   197   198   199   200   201   202   203