Page 208 - Elements of Chemical Reaction Engineering 3rd Edition
P. 208

180                                   Isothermal Reactor Design   Chap. 4

                             Stoichiometry. Using Equation (3-45) to substitute for the concentrations of A and
                             B in terms of the molar flow rates, we have for  T = To and P  = Po gives


                                                                                      (E4-9.4)


                                                                                      (E4-9.5)

                             where the total molar flow rate, FT, is just the sum of the flow rates of A and B:
                                                       FT= FA+FB                      (E4-9.6)

                             For every 1 mol of A disappearing 2 mol of B appear:
                                                        YB = 2( - m)                  (E4-9.7)
                             and

                                                      FB = ~(FAo-FA)                  (E4-9.8)
                             The total molar flow rate

                                               F, = FA + 2FAO-   FA = 2FAo-  FA       (E4-9.9)
                             and the total concentration at the entrance to the reactor (Po, To) is calculated from
                             the equation
                                                Po  -      4.1 atm          mol
                                                   -
                                          CTO z - -      dm3. atm (500  K)  = 0.1-  dm3   (E4-9.10)
                                               RTo   0.082-
                                                          mol. K
                                                                                     (E4-9.11)


                                                               FB
                                                    ‘B  = ‘TO  2FA0 - FA             (E4-9.12)

                                               TABLE  E4-9.1.  POLYMATH PROGRAM
                                    Equations                                   Initial  Values

                               d(fa)/d(v)=ra                                         10
                               ka=2. I
                               kc=l. 2
                               ctOz.1
                               fa0=10
                               fb=2* (faO-fa)
                               ft=2*faO-fa
                               ca=ctO*fa/ft
                               cb=ctO’fb/ft
                               ra=-ka*(ca-cb**2/kC)
                               rb=-2 ’ra
                               vo  =  0.   v  f  =  100
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