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               176                                                                              Mass Transfer and Diffusion


               coefficient of hydrogen sulfide to be different than the
               diffusion coefficient of hydrogen, because these are two
               different chemical species. However, the dispersion coef-
               ficient of hydrogen sulfide in the smoke will be the same
               as the dispersion coefficient of the hydrogen in the smoke
               because the mechanism is not that of molecular motion,
               but rather of velocity fluctuations.
                 Dispersion coefficients are usually much greater than
               diffusion coefficients and cause much more rapid mixing
               than would ever be possible from molecular motion alone
               (Cussler, 1997). In particular, for turbulent flow in a pipe,
               the dispersion coefficient is given by
                                  E = dv/2               (28)

               where d is the pipe diameter and v is the average velocity
               of the fluid in the pipe. However, if the flow in the pipe is
               laminar instead of turbulent, the corresponding result is
                                       2 2
                                      d v
                                 E =                     (29)
                                      192D                       FIGURE 5 Two easy mass transfer examples. In the unsteady
                                                                 case in (a), the water evaporates into the air. In the steady-state
               Thus in turbulent flow, the dispersion coefficient is inde-
                                                                 case in (b), the spheres are always wet with water, which again
               pendentofthediffusioncoefficient,butinlaminarflow,the  evaporates.
               dispersion coefficient depends inversely on the diffusion
               coefficient. This counterintuitive inverse dependence, the
                                                                 where c 1 is the concentration of water vapor in the volume
               result of axial convection coupled with radial diffusion,
                                                                 V of the box, A is the surface area of the water, and N 1
               is the foundation of the Goulay equation describing peak
                                                                 is the interfacial flux of the evaporating water. The idea
               spreading in chromatography. We now return from this
                                                                 that the total amount of water which evaporates is propor-
               dispersion tangent back to diffusion and in particular, to
                                                                 tional to the area is straightforward: after all, that’swhywe
               mass transfer.
                                                                 spread out rain drops on a tennis court in order to dry the
                                                                 tennis court faster.
                                                                   The flux N 1 is closely related to the flux j 1 used in
               III. MASS TRANSFER
                                                                 the diffusion section (Cussler, 1997; Taylor et al., 1993).
                                                                 The flux here differs because it potentially includes both
               We now turn to a completely different method of describ-
                                                                 diffusion and diffusion-induced convection, a distinction
               ing diffusion, one that has its greatest value in industrial
                                                                 which is unimportant when the solute is dilute. We will
               situations. It is related to both diffusion and dispersion but
                                                                 discuss only that case here. We also will assume that the
               has a simpler mathematical description. This means that
                                                                 flux at the interface N 1 is given by
               it’s more approximate. Unfortunately, it’s complicated by

               questions of units and definitions, which give it a reputa-       N 1 = k c 1(sat) − c 1      (32)
               tion of being a difficult subject.
                 To understand mass transfer, imagine that we have a  where c 1(sat) is the water concentration at the interface,
               small amount of water in a large box like that shown in  which is at saturation. If the air is initially dry, we can
               Fig. 5a. The air in the box is originally dry. We want to de-  combine Eqs. (31) and (32) and integrate to find
               scribe the water concentration in the box—the humidity—            c 1      −kat
               as a function of time. Again, we begin with a mass balance            = 1 − e                (33)
                                                                                  c 10
               like the following
                                                                 where a (= A/V ) is the liquid area per system volume
                  accumulation = [flow in − out] + evaporation  (30)  and k is a new rate constant, called unpoetically a mass
                                                                 transfer coefficient. This simple exponential is the most
               Because there is no flow in or out of the box, those terms
                                                                 common result of analysis of mass transfer.
               are zero and the mass balance simply becomes
                                                                   Similar relationships can be developed for steady-state
                                  dc 1                           mass transfer. For example, imagine that we have dry air
                                V     = AN 1             (31)
                                   dt                            flowing evenly through a bed of wet spheres, like those
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