Page 91 - Academic Press Encyclopedia of Physical Science and Technology 3rd Organic Chemistry
P. 91

P1: LLL/LLL  P2: FJU Final Pages
 Encyclopedia of Physical Science and Technology  EN002C-80  May 25, 2001  20:18







              Carbohydrates                                                                               399

              hydrolysate will reveal that one monomer (A in A–B–A
              and B in B–A–B) occurs in double the amount of the
              other; this monomer must be terminally located in the
              trisaccharide molecule. To illustrate this method, a nonre-
              ducing trisaccharide, raffinose, will be used as an exam-
              ple of a trisaccharide having three different monomers
              (A–B–C) (Scheme 21). On partial hydrolysis with acids,
              this trisaccharide affords a reducing disaccharide [6-(α-
              D-galactopyranosyl)-D-glucopyranose], and on enzymatic
              hydrolysis it yields a nonreducing disaccharide sucrose
              [α-D-glucopyranosyl-β-D-fructofuranose]. The common
              monomer in both disaccharides, D-glucopyranose, must
              therefore be located at the center of the trimer. The other
              two monomers (D-galactopyranose and D-fructofuranose)
              are then assigned positions at both ends of the nonreducing
              trimer. Oxidation (or reduction) of the first disaccharide,
              followed by hydrolysis, will reveal that D-glucose is at
              the reducing terminus and D-galactose is at the nonreduc-
              ing ends of the dimer molecule and confirm the location
              of the latter at one of the nonreducing ends of the trimer
              molecule. Since the second disaccharide is nonreducing,
              the terminal D-fructofuranose must be attached through
              C-2 to C-1 of D-glucose. This establishes the structure
              of raffinose as O-α-D-galactopyranosyl-(1 → 6)-O-α-D-
              glucopyranosyl-(1 → 2) O-β-D-fructofuranoside.



                c. Monosaccharide sequence in tetrasaccharides.
              The sequence in tetrasaccharides can be deduced by deter-
              mining the sequence of monosaccharides in the oligosac-
              charides that result from their partial hydrolysis (two
              trisaccharides and three disaccharides). If the tetrasaccha-
              ride is composed of four different monomers (A–B–C–D),
              the monosaccharide sequence can be deduced by deter-
              mining the monomer sequence in the disaccharides (A–B,
              B–C, and C–D) produced by partial hydrolysis. Use is
              made of the fact that the monomers common to two dimers
              (B, found in A–B and B–C; and C, in B–C and C–D) must
              be linked together and must be located in the center of the
                                                                SCHEME 21 Formation of melibiose and sucrose from raffinose.
              tetramer. (Thus, B must be attached to A and C, and C
              attached to B and D.) The same rule applies if only one
              monomer is repeated and the two analogous monomers  In general, the structure elucidation of polymers be-
              are contiguous (as determined from the fact that one of  comes more difficult as the DP increases. However, be-
              the dimers is a homodisaccharide). Examples of such ho-  cause higher oligosaccharides are composed of repeating
              modisaccharides are A–A obtained from A–A–B–C; B–B  unitsseldomlargerthantetrasaccharidefragments(andof-
              obtained from A–B–B–C; and C–C produced from A–B–  ten composed of mono-, di- or trisaccharides), the number
              C–C. If, on the other hand, the repeating monomers are  of possible oligosaccharides liberated on partial hydrol-
              not contiguous but are separated by one monomer (as in  ysis remains relatively small. Thus, whereas a tetrasac-
              A–B–A–C and A–B–C–B) or by two monomers (as in    charide (A–B–C–D) will afford on partial hydrolysis two
              A–B–C–A), a study of the dimers alone may not suffice  trisaccharides (A–B–C and B–C–D) and three disaccha-
              to elucidate the structure of the tetramer, making it neces-  rides (A–B, B–C, C–D), an octasaccharide (or for that
              sary to study also the structure of the two trisaccharides  matter a polysaccharide) composed of the same tetrasac-
              resulting from its partial hydrolysis.            charide repeating unit will afford only two additional
   86   87   88   89   90   91   92   93   94   95   96