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              Boron Hydrides                                                                              307

                                            H              H   H              H    H             H
                        H       H       H          H                  H                   H
                            B       B          B       B          B       B           B       B
                                                                                         H
                                                                      B
                          H       H   H      H     B      H     H H          H      H      B    H
                                B
                                                    H
                            B      B           B       B          B       B            B      B
                        H       H      H           H                  H                   H
                                            H             H    H             H     H              H


              Acombinationorresonancehybridofthesefourstructures  1. The total number of three-center bonds will equal the
              produces a more symmetrical molecule where all of the  number of boron atoms minus the charge because
              four borons around the base of the square pyramid are  each extra electron in the charge will lower the
              equivalent. This is in agreement with the known structure.  electron deficiency by one.
              As boron hydrides get larger or more symmetrical, the
                                                                                  s + t = p − c
              numbers of individual structures making up the hybrid get
              to the point where it is essentially unmanageable. For these  2. The hydrogen atom balance will be the same as for
              molecules the molecular orbital theory, which constructs  the neutral boron hydrides.
              orbitals for bonding from the atomic orbitals of multiple
                                                                                    s + x = q
              atoms, is appropriate.
                                                                3. The electron balance now must include the electrons
                                                                  imparting the charge. Besides the p pairs of electrons
              IV. ISOELECTRONIC COMPOUNDS:                        from the B H groups, each negative charge results in
                 BORON HYDRIDE ANIONS                             one-half a pair more of electrons that are available for
                 AND CARBORANES                                   the s, t, y, and x structural features.
                                                                                    c          q
                                                                                p +   = t + y +
              We will consider two important groups of compounds that               2          2
              share the same kinds of geometries as boron hydrides, that  The solution of these equations for the BH ion are
                                                                                                      −
                                                                                                      4
              is, can be viewed as polyhedra or polyhedral fragments.  s = 0, t = 0, y = 0, since none of these features is possible
              These are the boron hydride anions and carboranes. In  withasingleboronatom,and x = 3.Thisisastructurewith
              many cases the boron hydrides and compounds in these  no three-center bonds or boron-boron two-center bonds
              groups are isoelectronic (same number of valence elec-  and with three extra terminal hydrogen atoms on the single
              trons), and in these cases the structures are isostructural  boron atom.
              with almost the same geometric arrangement of atoms.  The known boron hydride anion with three boron atoms
                                                                     −
                                                                is B 3 H , for which the styx solutions are 2013 and 1104.
                                                                     8
                                                                Reasonable structures can be built using either of these
              A. Boron Hydride Anions
                                                                solutions. X-ray diffraction studies show that the correct
              Anions containing only boron and hydrogen are well  structure, at least in the solid phase, is 2013.
              known. The simplest of these is the borohydride or tetrahy-
                           −
              droborate ion BH , which with its tetrahedral geometry is  H   H
                           4                                                                   H  H
              isoelectronic and isostructural with the methane molecule.   B                H
              The borohydride anion is a very well-known reducing                              B
              agent in organic chemistry.
                                                                       B      B        H               H
                The are a number of boron hydride anions with more                         B       B
              than one boron atom, and these follow the same bond-  H   H   H    H     H       H        H
              ing principles as the neutral boron hydrides discussed in
              previous sections. That is, their structures can again be
              viewed as polyhedra that may have one or more vertices    2013                  1104
              removed. The numbers of the structural features, s, t, y,
              and x, will again depend on equations of balance, which
                                                                  1. Boron Hydride Anions and Wade’s Rules
              need to be modified to account for the negative charge.
              For a boron hydride anion with the formula B p H −c  the  Larger boron hydride anions can be evaluated as poly-
                                                     p+q
              equations will be                                 hedral fragments just as can the neutral boron hydrides
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