Page 128 - Engineered Interfaces in Fiber Reinforced Composites
P. 128

Chapter 4.  Micromechanics of stress transfer   111


                   .Zm(Y1Z)  = az,(u,z) +  [b21n(r/u) - v] [q~,,(b,z) - 0'~(a,z)1   (4.53)
                                        (b2 - a*)[( 1 + y) In(b/a) - 1/21   1

               where  (T'm(u7z)(= a$-(.))  and a',(b,z) are  the  MASS at the  fiber-matrix  interface
                (Y  = u) and the cylindrical surface (at Y  = b), respectively. Further, combining Eqs.
               (4.50) and (4.52) yields the MAS at the cylindrical surface


                                                                                 (4.54)


               where the coefficient & is a function of the elastic properties and geometric factors
               of the constituents, and is given by



                                                                                 (4.55)


               Therefore, combining Eqs. (4.12) and (4.50E(4.54) gives a differential equation for
               the FAS as


                                                                                 (4.56)


               where

                                       11 (1 + ;)
                   B"-         u2 [(!)2-                                         (4.57)
                    2-
                        (1 +7){(;j41n(;)   -+-f[(:)'+l]}   .

               The solution of Eq. (4.56) and the corresponding solutions for thc IFSS arc obtaincd
               for the boundary conditions

                                                                                 (4.58)
                   O-gW. - e))  = CJt
               for the partially  debonded interface as a general case. Thus:


                                                                                 (4.59)


                                                                                 (4.60)

               The  corresponding  solutions  for  the  fully  bonded  interface  can  be  obtained  by
                substituting ap  = 0 when e= 0 in  Eqs. (4.59) and (4.60).
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