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106               Engineered interfaces in fiber reinforced  composites

                    Substituting the solutions for the three major stress components determined in the
                    bonded  and debonded regions, a fiber-matrix  interface debond criterion is derived
                    as

                                                            ,
                        27~aGi, = B3u2 + C,(F + C)C + D3(F + c)~                      (4.37)
                    where the coefficients B3, C3  and 03 are the complex functions of material properties
                    of the constituents and geometric factors, and are given in Appendix B. Therefore,
                    the stress applied to the matrix at the remote ends, o, = bod(=  a(b2 - a2)/b2), for
                    debond crack propagation  is obtained


                                       2naGiC                        'I2 -   C3 +2D3
                             Yb2
                        Cod  = a2 { [ (B3 + C3 + D3)2 + 4(B3 + C3 + 03)   2(B3 + C3 +D3)'}   '
                                                                                      (4.38)

                    4.2.3.3. Fiber fragmentation
                      When the external stress is sufficiently high to cause the maximum FAS to reach
                    the local fiber tensile strength at the fiber center, the fiber fractures. A fiber tensile
                    strength model is used in this analysis to predict  the average strength of the fiber
                    corresponding to a given gauge length based on the Weibull probability of failure
                    (Weibull, 195 1). According to the cumulative failure probability function proposed
                    by van der Zwaag (1989), the average fracture stress of length (2L0) is given by


                                                                                      (4.39)

                    where m and  cu are the  Weibull modulus  and  scale factor,  and  r is the  gamma
                    function. Therefore, the average tensile strength of the fiber segment of length (215) is
                    given by


                                                                                      (4.40)


                    Since the loading is assumed to be perfectly symmetrical about the fiber center, fiber
                    breakage is always expected to occur at the center  (z = 0)
                        4(0) = OTS(2L)  .                                             (4.41)

                    The maximum FAS at z  = 0 can be determined from Eqs. (4.25) and (4.31)


                                            .I> sech &(L   - t)                       (4.42)
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