Page 82 - Essentials of physical chemistry
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44                                                   Essentials of Physical Chemistry


                          df (v)          m    3=2   2mv   mv 2  2   mv 2
                               ¼ 0 þ 4p                  e   2kT v þ 2ve   2kT ¼ 0:
                           dv           2pkT       2kT
            The first zero on the right side is due to the derivative of the constants and the other terms are due to
                           mv 2
            the product of v e  2kT . Strictly speaking, we see that this derivative can indeed be zero when v is
                         2
            zero and again when v becomes very large in the negative exponent, but we are interested in the flat

                                                      mv 2           m  2
            spot at the top of the peak. Thus, we cancel out ve   2kT to leave only  v þ 2 ¼ 0, and so we
                                                                     kT
                                          r ffiffiffiffiffiffiffiffi  r ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi  r ffiffiffiffiffiffiffiffiffi
                                            2kT    2kTN Av    2RT
                                                                  .
                                             m      mN Av      M
            find the most probable speed as a ¼  ¼         ¼
                                            m        mv 2  2
                                                 3=2
              It is difficult to graph f (v) ¼ 4p   e   2kT v when you insert the tiny mass ‘‘m’’ and
                                          2pkT
            use the high velocities that occur. However, we can consider a simpler function that has the
            same variable dependence by using f (x) ¼ e  x 2 x 2  as shown in Figure 3.3. The derivative
            df      3  x 2     x 2
              ¼ 2x e     þ 2x e  ¼ 0 ) x max ¼ 1. We see on the graph that the maximum does indeed
            dx
            occur at x ¼ 1, but the shape of the curve is asymmetrical and any weighted average using this
            distribution will favor higher values of x. By analogy, Figure 3.4 shows that the shape of the
            Boltzmann distribution is not symmetric and extends out to the higher speeds. However, the most
            important result from the Boltzmann analysis is that now we know the true average speed:
                            r ffiffiffiffiffiffiffiffiffi  r ffiffiffiffiffiffi          r ffiffiffiffiffiffiffiffiffi  r ffiffiffiffiffiffi
                              2RT         RT                 8RT         RT
                                  ffi 1:414    ,                   ffi 1:596    ,  and
                     V max ¼                   hVi¼ V ave ¼
                              M            M                 pM           M
                                              r ffiffiffiffiffiffiffiffiffi  r ffiffiffiffiffiffi
                                                3RT          RT
                                                    ffi 1:732    :
                                        V rms ¼
                                                 M           M




























            FIGURE 3.3 Ludwig Eduard Boltzmann (1844–1906) was an Austrian physicist, who founded the fields of
            statistical mechanics and statistical thermodynamics. (Image courtesy of Chemical Heritage Foundation
            Collections.)
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