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                                                                                              5.2 Fluid Transport  171


                                                                                                       3
                                                The nomogram (C   100) of Fig. 5.6 for D   400 mm and Q   0.210 m /s will give
                                                s   11%
                                                           h f    sL   11‰   3,300 m   36 m
                                                           P A      580   30   600   36
                                                           P A      86 m or 8.6 bars is the actual pressure at point A






                     EXAMPLE 5.7   APPLICATIONS OF HAZEN-WILLIAM FORMULA
                                         Determine the expected velocity, full flow and headloss for a 24-in. (609.6 mm) circular conduit
                                         with a Hazen-William coefficient C   100, a length L   1,000 ft (304.8 m), and a hydraulic gra-
                                          dient s   2.25%.

                                          Solution 1 (U.S. Customary System):
                                             1. According to the nomogram shown in Fig. 5.6,
                                                                                      3
                                                                  v   3.3 ft/s and Q   10. ft /s
                                                                  s   0.0025   h f /L   h f /1,000 ft
                                                                  h f   1,000 ft   0.0025   2.5 ft
                                             2. Using Eq. 5.34 and Eq. 5.36,
                                                    v   0.115 cd 0.63 0.54    0.115   100(24) 0.63 (0.0025) 0.54    3.3 ft/s
                                                                s
                                                                s
                                                    v   0.55 CD 0.63 0.54    0.55   100(24/12) 0.63 (0.0025) 0.54    3.3 ft/s
                                                                                                       3
                                                                 s
                                                 Q ft /s   0.432 CD 2.63 0.54    0.432   100(24/12) 2.63 (0.0025) 0.54    10.5 ft /s
                                                   3
                                                   h f   1,000 ft   0.0025   2.5 ft
                                          Solution 2 (SI System):
                                             1. According to the nomogram shown in Fig. 5.6,
                                                                                      3
                                                                  v   1 m/s and Q   0.28 m /s
                                                                  h f   304.8 m   0.0025   0.762 m
                                             2. Using Eq. 5.34 and Eq. 5.36,
                                                                  s
                                                    v   0.3545 CD 0.63 0.54    0.3545   100(0.6096) 0.63 (0.0025) 0.54    1 m/s
                                                                                                         3
                                                                 s
                                                 Q m /s   0.278 CD 2.63 0.54    0.278   100(0.6096) 2.63 (0.0025) 0.54    0.298 m /s
                                                   3
                                                   h f   304.8 m   0.0025   0.762 m


                    5.2.3  Form Resistance
                                         Pipeline transitions and appurtenances add form resistance to surface resistance. Head
                                          losses are stepped up by changes in cross-sectional geometry and changing directions
                                          of flow. Expansion and contraction exemplify geometric change; elbows and branches,
                                          directional change. Valves and meters as well as other appurtenances may create both
                                          geometrical and directional change. With rare exceptions, head losses are expressed
                                                                             2
                                          either in terms of velocity heads, such as Kv >2g, or as equivalent lengths of straight pipe,
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