Page 49 - Fluid Power Engineering
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26    Cha pte r  T w o


               FIGURE 2.11
               Flow through
               a sharp-edged
               orifi ce.









                   Referring to Fig. 2.11, the fluid particles are accelerated from velocity
               v  at section 1 to the jet velocity, v , at section 2 through a sharp-edged
                1                           2
               orifice. The fluid flow between sections 1 and 2 is nearly streamlined or
               potential flow, which justifies the application of Bernoulli’s equation
               between these two sections.

                                           2
                                   v −  v =  ( P −  P )             (2.30)
                                        2
                                    2
                                    2  1  ρ  1   2
                   The term (P − P ) is the pressure difference required to accelerate
                            1   2
               the fluid from the lower upstream velocity (v ) to the higher jet veloc-
                                                     1
               ity (v ). The kinetic energy of the jet is not recovered. It is converted
                    2
               into thermal energy, increasing the fluid temperature, and the pres-
               sures at sections 2 and 3 are practically equal.
                   The area of the jet (A ) is smaller than the orifice area (A ) due to
                                    2                             0
               the fluid inertia. The point along the jet where the area becomes a
               minimum is called vena contracta. The contraction coefficient is de-
               fined as
                                      C =  A A                      (2.31)
                                            /
                                       c   2  0
                   Assuming an incompressible fluid, the application of the continu-
               ity equation yields

                                      Av =  A v                     (2.32)
                                       11    2 2
                   Considering Eqs. (2.30) to (2.32), the following expression is
               deduced for the jet velocity, v :
                                        2
                                       1        2
                             v =                 ( P −  P )         (2.33)
                              2             2   ρ  1  2
                                   1 − ( AA )
                                        /
                                        2  1
                   Actually, the jet velocity is slightly less than that calculated by
               Eq. (2.33), due to the losses caused by the viscous friction. This friction
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