Page 64 - Fluid Power Engineering
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Hydraulic Oils and Theor etical Backgr ound    41



























               FIGURE 2.21  Effect of absolute pressure on the air solubility in a typical
               mineral-based hydraulic oil at constant temperature.


               volume of the undissolved air is V at the standard atmospheric con-
                                            i
               ditions, T = 288.15 K and P = 100 kPa (abs). The pressure is increased
                       i              i
               to P. The new volume becomes V and its temperature increases by ΔT.
               The temperature increment is calculated as follows:
                              PV =  P V =  PV = constant            (2.86)
                                             k
                                       k
                                 k
                               ii    2  2
               where k is the adiabatic exponent (k = 1.4) and the pressure is
               absolute.


                               P   ⎛ V ⎞ k   V   ⎛ P⎞ 1/ k
               Then              =  ⎜  i ⎟   or   =  ⎜ ⎟            (2.87)
                                                   i
                               P   ⎝  V ⎠    V   ⎝  P ⎠
                                i             i
                             PV =  mRT  and  PV =   mRT             (2.88)
                              ii      i        22       2


                                                  ⎧ ⎧  k−1  ⎫
                                      ⎛ P V ⎞      ⎛ ⎪  P⎞  k  ⎪
               Then      ΔT =  T −  T =  T i ⎜  −  T =  T ⎨  − 1 ⎬  (2.89)
                                                  i ⎜ ⎟
                                      ⎝  P V ⎠    ⎪ ⎝  P ⎠  ⎪
                                 i        ⎟   i
                                                     i
                                          i
                                       i
                                                  ⎩         ⎭
                   Equations (2.87) and (2.89) were used to calculate the volume reduc-
               tion and temperature increment due to the sudden increase of pressure.
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