Page 59 - Fluid Power Engineering
P. 59

36    Cha pte r  T w o


               FIGURE 2.20
               Axial pipe wall
               deformation.










                   Considering the actual dimensions and parameters of transmis-
               sion lines used in hydraulic power systems, the term ΔD is negligible
               compared to 2D, then, Eq. (2.71) becomes

                                   π L        π    ⎛  D ⎞
                                         2
                                            )
                                         (
                                                 2
                             ΔV   =   ΔDD =     D L ⎜  ⎟  ΔP        (2.72)
                                LR  4          4   ⎝  Eh⎠
                   Figure 2.20 illustrates the effect of pressure forces in the axial
               direction. The volumetric variation due to axial wall deformation,
               V , can be calculated as follows:
                 LA
                                   πD Δ P  DP
                                             Δ
                                      2
                                σ =       =     = E ε               (2.73)
                                    4 πDh   4 h     a
                                   Δ L
                               ε =                                  (2.74)
                                a   L

                               ΔL =  ΔPDL                           (2.75)
                                    4 Eh

                                   π        π   ⎛  D ⎞
                                               2
                             ΔV   =  D 2 ΔL =  D L ⎜  ⎟  ΔP         (2.76)
                               LA  4        4   ⎝ 4 Eh⎠
                   The total variation of line volume is

                                        π    ⎛ 5 D ⎞      ⎛ 5 D ⎞
                      ΔV =  ΔV  +  ΔV  =  D L ⎜  ⎟ ΔP =  V ΔP ⎜ ⎜  ⎟  (2.77)
                                           2
                        L     LR    LA         Eh⎠          Eh⎠
                                        4    ⎝ 4          ⎝ 4
                   By substituting Eqs. (2.58), (2.59), and (2.77) in Eq. (2.61), the follow-
               ing relation is obtained:

                                                         D ⎞
                               in ∑
                          ∫ (∑ Q −  Q )  dt −  V  Δ P = Δ  ⎛ 5 Eh⎠ ⎟  (2.78)
                                                      ⎜
                                                   V P
                                      out
                                                      ⎝ 4
                                            B
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